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KatRina [158]
3 years ago
7

Playland Park charges $25 admission plus $2 per ride. Funland Park charges $35 admission plus $1 per ride. For what number of ri

des is the total cost the same at both parks? Does any body know the answer to this question?
Mathematics
1 answer:
Ket [755]3 years ago
8 0

Answer:

10 rides

Step-by-step explanation:

Make an equation.

25 + 2x = 35 + 1x

Subract 1x from the 2x to get 1.

New Equation: 25 + 1x = 35

Subtract 25 from 35 to get 10.

New Equation: 1x = 10

Divide 1 from both sides.

Answer: 10 rides

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Which two fractions have a sum of - 7/24
Feliz [49]
The two fractions that added together give you a sum of -7/24 are 1/24+-8/24= -7/24
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4 years ago
Susan is looking to hire a cleaning company to clean her house every week. One cleaning company's cost can be calculated by the
kirill [66]

Answer:

<h3>A. 1 hour</h3>

Step-by-step explanation:

If one cleaning company's cost can be calculated by the expression 75 + 50x, where x is the amount of hours they spend cleaning and another cleaning company's cost can be calculated using the expression 50 + 75x, then to calculate how long each company will have to clean to cost the same amount, we will equate both expression of the company cost and solve for x as shown;

On equating:

75 + 50x,  =  75x + 50

collect like terms'

50x-75x = 50-75

-25x = -25

divide both sides by -25

-25x/-25 = -25/-25

x = 1

hence the number of hours each company will have to clean to cost the same amount is 1 hour

3 0
3 years ago
100 + 5 x 4 + 4^3<br><br> Don’t mind this .....
tatiyna

Answer:

184

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
"A cable TV company wants to estimate the percentage of cable boxes in use during an evening hour. An approximation is 20 percen
Marizza181 [45]

Answer:

The company should take a sample of 148 boxes.

Step-by-step explanation:

Hello!

The cable TV company whats to know what sample size to take to estimate the proportion/percentage of cable boxes in use during an evening hour.

They estimated a "pilot" proportion of p'=0.20

And using a 90% confidence level the CI should have a margin of error of 2% (0.02).

The CI for the population proportion is made using an approximation of the standard normal distribution, and its structure is "point estimation" ± "margin of error"

[p' ± Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }]

Where

p' is the sample proportion/point estimator of the population proportion

Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} } is the margin of error (d) of the confidence interval.

Z_{1-\alpha /2} = Z_{1-0.05} = Z_{0.95}= 1.648

So

d= Z_{1-\alpha /2} * \sqrt{\frac{p'(1-p')}{n} }

d *Z_{1-\alpha /2}= \sqrt{\frac{p'(1-p')}{n} }

(d*Z_{1-\alpha /2})^2= \frac{p'(1-p')}{n}

n*(d*Z_{1-\alpha /2})^2= p'(1-p')

n= \frac{p'(1-p')}{(d*Z_{1-\alpha /2})^2}

n= \frac{0.2(1-0.2)}{(0.02*1.648)^2}

n= 147.28 ≅ 148 boxes.

I hope it helps!

3 0
4 years ago
SOMEBODY HELP MEEE!!!!
VladimirAG [237]
Solution= x=5
Alernative form= 21 x - 105= 0<span />
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