Let
x-------> the first number
y-------> the second number
we know that
equation 1
equation 2
substitute the equation 1 in equation 2
![[-5-y]*y=-90 \\ -5y- y^{2} =-90 \\ y^{2} +5y-90=0](https://tex.z-dn.net/?f=%5B-5-y%5D%2Ay%3D-90%20%5C%5C%20-5y-%20y%5E%7B2%7D%20%3D-90%20%5C%5C%20y%5E%7B2%7D%20%2B5y-90%3D0)
using a graphical tool to resolve the second order equation
see the attached figure
the numbers are-12.3117.311
For the answer to the question above asking <span>what is the probability that a randomly selected student will be a boy that brings his lunch to school? I'll provide a solution for the following problem below.
</span>P(boy |lunch) = P(boy and lunch)/P(lunch) = 0.40
P(boy and lunch) = P(lunch)*0.4 = 0.3*0.4 = 0.12
Volume of a Square Pyramid: 1/3 x length x width x height
Length = 2
Width = 2
Height = 3
Volume = 1/3 x 2 x 2 x 3
Volume = 1/3 x 4 x 3
Volume = 1/3 x 12
Volume = 4
Volume = 4 cm^3
Hope this helps!
Answer: The answer is F.
Step-by-step explanation: It’s F because the number would be multiplied equally because all of the number are multiplied by 2. The rest of them either have variables or variables with numbers in them, which looks kind of funky, so F is the answer. I hope you get it right :). Sorry, if I was late for the reply and if you already figured it out… :(.
