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3 years ago

1. How long is 50% of 60 minutes? 2. How long is 10% of 60 minutes? 3. How long is 75% of 60 minutes?

Mathematics

2 answers:

babunello [35]3 years ago

7 0

Answer:

50% of 60 minutes is 30,

10% of 60 minutes is 6,

75% of 60 minutes is 45.

Step-by-step explanation:

50 is half of 100 so 30 would be half of 60.

Bezzdna [24]3 years ago

4 0

Answer:

Step-by-step explanation:

50% = 0.5

10%=0.1

75%=0.75

$60*0.5=30min\\2.\\60*0.1=6min\\\\3.\\60*0.75=45min$

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If Denise and Alex add a 15% tip after the tax is applied, what is the total cost, including tip?

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3 years ago

Y+3=2(x-1) im not so sure that i got the answer correct.

Vikentia [17]

So just try it for x=1 how many will get for y

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3 years ago

Help me :,)

IrinaK [193]

Answer:

The rule of the arithmetic sequence is 13 - 2n

The 30th term is -47

Step-by-step explanation:

∵ f(n) = 11 and g(n) = -2(n - 1) = -2n + 2

∴ f(n) + g(n) = 11 + -2n + 2 = 13 - 2n

Use n = 1 , 2 , 3 , 4 to check the type of the sequence

∵ n = 1 ⇒ 13 - 2(1) = 11

∵ n = 2 ⇒ 13 - 2(2) = 13 - 4 = 9

∵ n = 3 ⇒ 13 - 2(3) = 13 - 6 = 7

∵ n = 4 ⇒ 13 - 2(4) = 13 - 8 = 5

∵ 11 , 9 , 7 , 5 is an arithmetic sequence with difference -2

∴ The rule of the arithmetic sequence is 13 - 2n

∴ The 30th term = 13 - 2(30) = -47

5 0

3 years ago

Read 2 more answers

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second

Molodets [167]

Given:

In a set of 3 numbers the first is a positive integer, the second is 3 more than the first and the 3rd is a square of the second.

To find:

The equation for the given situation if the sum of the numbers is 77.

Solution:

a. Let the first number in the set is x.

The second is 3 more than the first. So, the second number is $(x+3)$ .

The 3rd number is a square of the second. So, the third number is $(x+3)^2$ .

Therefore, the first, second and third numbers are $x,(x+3),(x+3)^2$ respectively.

b. The sum of the numbers is 77.

First number + Second number + Third number = 77

c. So, the equation in terms of x is:

$x+(x+3)+(x+3)^2=77$

Therefore, the required equation is $x+(x+3)+(x+3)^2=77$ .

d. On simplification, we get

$x+x+3+x^2+6x+9=77$ $[\because (a+b)^2=a^2+2ab+b^2]$

$x^2+(6x+x+x)+(3+9)=77$

$x^2+8x+12=77$

Subtract 77 from both sides.

$x^2+8x+12-77=77-77$

$x^2+8x-65=0$

Therefore, the simplified form of the required equation is $x^2+8x-65=0$ .

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