Here is the solution for finding mean mode and median
Answer:
10
30%
Step-by-step explanation:
In this case it would be the combination of 2 taken from 5.
That is, when n = 5 and r = 2
nCr = n! / r! * (n-r)!
replacing
5C2 = 5! / (2! * 3!)
5C2 = 10
Which means that the sample space is 10 possible combinations.
the probability that the card you draw is even is 3/5, since there are 3 even cards that exist and 5 is the total number of cards.
Now, so that both are for it would be the multiplication of the previous probability and 2/4 because an even card and a card in general have already been drawn:
(3/5) * (2/4) = 0.3
So the probability that both are even is 30%
Answer:
<h2>(A) 9</h2>
Step-by-step explanation:
Let’s put the number of the set 6, 10, 2, 7, 13, 15 in order from least to greatest :
2 , 6 , 7 , 10 , 13 , 15
we know that the median is the central value of the number set
then
if the median is 10
then x should be placed between 10 and 13 or 13 and 15
which means
x ≥ 10
therefore
9 could NOT be the value of x
Answer:
x=3
Step-by-step explanation:
subtract 5x from 7x
subtract 4 from 10
divide 2x and 6 by 2
