Answer:
The largest total area that can be enclosed will be a square of length 272 yards.
Step-by-step explanation:
First we get the perimeter of the large rectangular enclosure.
Perimeter of a rectangle =2(l + w)
Perimeter of the large rectangular enclosure= 1088 yard
Therefore:
2(L+W)=1088
The region inside the fence is the area
Area: A = LW
We need to solve the perimeter formula for either the length or width.
2L+ 2W= 1088 yd
2W= 1088– 2L
W = 
W = 544–L
Now substitute W = 544–L into the area formula
A = LW
A = L(544 – L)
A = 544L–L²
Since A is a quadratic expression, we re-write the expression with the exponents in descending order.
A = –L²+544L
Next, we look for the value of the x coordinate


L=272 yards
Plugging L=272 yards into the calculation for area:
A = –L²+544L
A(272)=-272²+544(272)
=73984 square yards
Thus the largest area that could be encompassed would be a square where each side has a length of 272 yards and a width of:
W = 544 – L
= 544 – 272
= 272 yards
Answer:
Step-by-step explanation:
8x² + 2(x²-1) = 8x² + 2*x² - 2*1
= 8x² + 2x² -2
= 10x² -2
Like terms: 8x² , 2x²
1/3 of 240 is 240/3 which is 80 dollars.
Answer:
a. k > 7
b. a < -21
c. h > 9
d. f < 301
Step-by-step explanation:
a. 2k + 7 > 21
2k > 14
k > 7
b. a/3 + 12 < 5
a/3 < -7
a < -21
c. 6h − 5 > 49
6h > 54
h > 9
d. f/7 − 9 < 34
f/7 < 43
f < 301
Hope this helps!