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Grace [21]
3 years ago
8

A 35 foot wire is secured from the top of a flagpole to a stake in the ground. If the stake is 14 feet from the base of the flag

pole, how tall is the flagpole?

Mathematics
2 answers:
cupoosta [38]3 years ago
6 0

the answer is 21ft because the total is 35feet so 35 - 14 = 21



inessss [21]3 years ago
5 0

Answer:

Step-by-step explanation:

Given that,

The flag pole wire is 35foot

And the length of the foot from the tag flagpole is 14ft

So we want to know the height of the flagpole

So this will form a right angle triangle where the wire is the hypotenuse.

Then, using Pythagoras theorem

c² = a² + b²

35² = 14² + h²

35²-14² = h²

h² =1225-196

h² = 1029

h=√1029

h= 32.09ft

Then, the height of the flag pole is 32.08foot.

Check attachment for diagram.

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Step-by-step explanation:

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Read 2 more answers
A plane can fly 540 miles with the wind in one hour less than it can fly 480 miles against the wind. The average wind speed is 3
Bess [88]

Answer:

The speed of the plane in still air = 150 mph

Step-by-step explanation:

This is a relative velocity question

Let the velocity of the plane in still air be v

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(Velocity of the plane relative to the wind) = (velocity of plane) - (velocity of wind)

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(Velocity of plane relative to the wind) = (480/t)

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(480/t) = v - 30

t = 480/(v-30) (eqn 1)

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(Velocity of plane relative to the wind) = 540/(t-1)

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Since t is equal in both cases, substitute the value of t in eqn 1 into eqn 2.

[480/(v-30)] - 1 = [540/(v+30)]

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480(v+30) - [(v+30)(v-30)] = 540(v-30)

480v + 14400 - (v² - 900) = 540v - 16200

480v + 14400 - v² + 900 = 540v - 16200

v² + 540v - 480v - 16200 - 14400 - 900 = 0

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Solving the quadratic equation,

v = 150 mph or v = -210 mph

We'll pick the positive answer because of the directions we have established.

Therefore, the speed of the plane in still air = 150 mph

Hope this Helps!!!

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