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Lady bird [3.3K]

2 years ago

9

Given: RSTU is a parallelogram. SX = RX ST UX

2 answers:

HACTEHA [7]2 years ago

8 0

<h2>Answer:</h2>

<u>SX is equal to</u><u> UX</u>

<h2>Step-by-step explanation:</h2>

US and Rt are the lines which make the center of the parallelogram. Hence the center of both lines is X so both the lines must be present at the same distance from the mid point. US is divided in two equal parts on point X and we know that center point is always equidistant from the end points. X must be equidistant from both UX and SX so we can say that SX = UX.

oee [108]2 years ago

4 0

Sx is equal to ux cause the line has a point in the middle so they are equal

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12345 [234]

Answer:

$4x^2-21x-2$

Step-by-step explanation:

Given that:

Difference of two trinomials is $x^2 - 10x + 2$

One of the two trinomials is $3x^2 - 11x - 4$

To find:

The other trinomial = ?

Four options are:

$2x2 - x - 2 \\2x2 + x + 6 \\4x2 + 21x + 6\\ 4x2 - 21x - 2$

Solution:

Let the two trinomials be A and B.

Given A - B = $x^2 - 10x + 2$

B = $3x^2 - 11x - 4$

We have to find the other trinomial A.

A - B = $x^2 - 10x + 2$

A - ( $3x^2 - 11x - 4$ ) = $x^2 - 10x + 2$

$\Rightarrow$ A = $x^2 - 10x + 2$ + ( $3x^2 - 11x - 4$ )

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So, the correct answer is $4x^2-21x-2$ .

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3 years ago

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WINSTONCH [101]

Answer:

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Elis [28]

Answer:

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Step-by-step explanation:

Given

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<em>See attachment for circle</em>

Required

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From the attachment, we can see that:

$\angle ADC$ is at the circumference

$\angle ABC\\$ is in at the center

From cyclic theorems,

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Make ABC the subject

$\angle ABC = 2 * \angle ADC$

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