If there are 15 students who don’t wear glasses, how many students are in the class?

Anyone know the answer?

wariber [46]

Answer:

w=51

x=0

51-0=51

y=69

z=60

69+60=129

3 0

2 years ago

Point K is on line segment JL. Given KL = 6 and JK = 14, determine the length<br> JL.

mestny [16]

JL= 20

JK+KL= JL
14+6= 20

8 0

2 years ago

If you are asked to provide a set of two or more numeric answers, separate them with commas. For example, to provide the year th

garik1379 [7]

Answer: Perimeter = 66 cm and area = $66\ m^2$

Step-by-step explanation:

The perimeter of rectangle is given by :-

$P=2(l+w)$ , where l is length and w is width of the rectangle.

Given : A rectangle has a length of 5.50 m and a width of 12.0 m .

Then, the perimeter of rectangle :

$P=2(12+5.50)\\\\\Rightarrow\ P=2(17.50)=35\ m$

Also, area of rectangle is given by :-

$A=l\times w=5.50\times12=66 \ m^2$

Area of rectangle = $66\ m^2$

3 0

3 years ago

The arch beneath a bridge is semi-elliptical, a one-way roadway passes under the arch. The width of the roadway is 38 feet and

forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:

$\frac{x^2}{a^2}+\frac{y^2}{b^2}$

where:

a= wider side of the ellipse

b= shorter side of the ellipse

in this case:

$a=\frac{38}{2}=19ft$

and

b=12ft

so we can go ahead and plug this data into the ellipse formula:

$\frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}$

and we can simplify the equation, so we get:

$\frac{x^2}{361}+\frac{y^2}{144}$

So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

$\frac{y^{2}}{144}=1-\frac{x^{2}}{361}$

$y^{2}=144(1-\frac{x^{2}}{361})$

we can add everything inside parenthesis so we get:

$y^{2}=144(\frac{361-x^{2}}{361})$

and take the square root on both sides, so we get:

$y=\sqrt{144(\frac{361-x^{2}}{361})}$

and we can simplify this so we get:

$y=\frac{12}{19}\sqrt{361-x^{2}}$

and now we can evaluate this equation for x=4 (half the width of the trucks) so:

$y=\frac{12}{19}\sqrt{361-(8)^{2}}$

y=11.73ft

this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.

5 0

2 years ago

The jewelry center bought a pair of earrings for $250. They are going to mark the price of the earrings up 32.5%. How much will

ELEN [110]

Answer:

$331.25

Step-by-step explanation:

Given:

The jewelry center bought a pair of earrings for $250

They are going to mark the price of the earrings up 32.5%

Question asked:

How much will they sell the earrings for ?

Solution:

Cost price of a pair of earrings = $250

Mark up value = 32.5% of $250

= $\frac{32.5}{100} \times 250\\\frac{8125}{100} = 81.25$

Now, we can find selling price of a pair of earring by simply adding the cost price and the mark up value.

Selling price = cost price + mark up value

= 250 + 81.25

= $331.25

Thus, they sell the earrings for $331.25

4 0

3 years ago