A family dinner check was $38.82. Estimate a 15% tip

A 12-ft-by-15-ft rectangular swimming pool has a 3-ft-wide no-slip surface around it. What is the outer perimeter of the no slip

Nataliya [291]

Answer: 74 ft
12+12+15+15= 74
Perimeter is the distance around sometime

7 0

2 years ago

Which number can each term of the equation be multiplied by to eliminate the fractions before solving? 6 –3/4x +1/3 =1/2 x + 5

irga5000 [103]

Answer:

The number is 12.

Step-by-step explanation:

Given: $6-\dfrac{3}{4}x+\dfrac{1}{3}=\dfrac{1}{2}x+5$

We need to find a number multiply to each term to get rid of fraction.

We will find LCD of denominator.

First we see the numbers at denominator

Denominators are 4,3,2

Now, we will find the LCD of 2,3, and 4

Factor of 2: 2x1

Factor of 3: 3x1

Factor of 4: 2x2x1

LCD = 2x2x3 = 12

If we multiply by 12 to each term to eliminate the fraction.

Simplest equation:

$12\cdot 6-12\cdot \dfrac{3}{4}x+12\cdot \dfrac{1}{3}=12\cdot \dfrac{1}{2}x+12\cdot 5$

$72-9x+4=6x+60$

Hence, The number is 12.

5 0

3 years ago

Read 2 more answers

Does this graph represent a function? Why

Sladkaya [172]

C. Yes because it passes the vertical line test

3 0

1 year ago

20≥8+4.99x please I could get an F.

marin [14]

Answer:

$\begin{bmatrix}\mathrm{Solution:}\:&\:x\le \frac{1200}{499}\:\\ \:\mathrm{Decimal:}&\:x\le \:2.40480\dots \\ \:\mathrm{Interval\:Notation:}&\:(-\infty \:,\:\frac{1200}{499}]\end{bmatrix}$

Step-by-step explanation:

$20\ge \:8+4.99x\\Switch\:sides\\8+4.99x\le \:20\\\mathrm{Multiply\:both\:sides\:by\:}100\\8\cdot \:100+4.99x\cdot \:100\le \:20\cdot \:100\\Refine\\800+499x\le \:2000\\\mathrm{Subtract\:}800\mathrm{\:from\:both\:sides}\\800+499x-800\le \:2000-800\\Simplify\\499x\le \:1200\\\mathrm{Divide\:both\:sides\:by\:}499\\\frac{499x}{499}\le \frac{1200}{499}\\Simplify\geq \\x\le \frac{1200}{499}$

5 0

2 years ago

Needdd hellpppppssssssss

Ratling [72]

Answer:

Choice number one:

$\displaystyle \frac{5}{10}\cdot \frac{4}{9}$ .

Step-by-step explanation:

Let $A$ be the event that the number on the first card is even.
Let $B$ be the event that the number on the second card is even.

The question is asking for the possibility that event $A$ and $B$ happen at the same time. However, whether $A$ occurs or not will influence the probability of $B$ . In other words, $A$ and $B$ are not independent. The probability that both $A$ and $B$ occur needs to be found as the product of

the probability that event $A$ occurs, and
the probability that event $B$ occurs given that event $A$ occurs.

5 out of the ten numbers are even. The probability that event $A$ occurs is:

$\displaystyle P(A) = \frac{5}{10}$ .

In case A occurs, there will only be four cards with even numbers out of the nine cards that are still in the bag. The conditional probability of getting a second card with an even number on it, given that the first card is even, will be:

$\displaystyle P(B|A) = \frac{4}{9}$ .

The probability that both $A$ and $B$ occurs will be:

$\displaystyle P(A \cap B) = P(B\cap A) = P(A) \cdot P(B|A) = \frac{5}{10}\cdot \frac{4}{9}$ .

6 0

2 years ago