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irga5000 [103]
3 years ago
13

HELP ASAP AS SOON AS POSSIBLE AAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAAA

Mathematics
1 answer:
frez [133]3 years ago
5 0

Answer:

-18+12

Step-by-step explanation:

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Minchanka [31]

Answer:

1. x less than or equal to 1/3

2. x is less than 1

3. x is greater than 6

4. x is less than -2

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
The radius of a cylinder gift box is box is 3X +1 inches the height of the gift box is twice the radius what is the surface area
Genrish500 [490]

Answer:

The surface area of the gift box is = A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

Step-by-step explanation:

The surface area of the cylinder can be calculated using this formula:

A=2\pi rh+2\pi r^2

in this case, r is not a number, but rather an expression, which is r = 3x +1.

The height of the gift box is twice the radius, which is h = 2(3x+1)= 6x+2

To get our curved surface area, we carefully put the expressions for h and r into the equation.

A = 2 \times \frac{22}{7} \times (3x+1) \times (6x+2) + 2 \times \frac{22}{7} \times (3x+1)^{2}

A = \frac{44}{7} (3x+1) \times (6x +2) + \frac{44}{7} (9x^{2} + 6x +1)\\A =\frac{132}{7}x + \frac{44}{7} \times (6x+2)+ \frac{396}{7}x^{2}+\frac{246}{7}x +\frac{44}{7}

A = \frac{792}{7}x^{2} +\frac{264}{7}x +\frac{264}{7}x + \frac{88}{7} + \frac{396}{7}x^{2} + \frac{246}{7}x + \frac{44}{7}

A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

The surface area of the gift box is = A = \frac{1188}{7}x^{2}+ \frac{774}{7}x +\frac{132}{7}

5 0
4 years ago
I'm not sure if this is correct or not. I just learned how to plot these equations. Please tell me if i'm right or wrong and exp
solong [7]

Answer:

The graph you have is wrong. This is the right graph.

Hope this helps! Have a nice day, good luck, and stay safe!

8 0
3 years ago
NEED HELP. Show example too
user100 [1]

Answer:

Step-by-step explanation: antimay

6 0
3 years ago
HELP....someone plz solve this proof for me......<br>I'll give you 5stars and brainliest​
IceJOKER [234]

Answer:

1+cos^2(2A)=(1−cos2(2A))+2cos^2(2A)

=sin^2(2A)+2(cos^2A−sin^2A)^2

=(2sinAcosA)^2+2(cos^4A−2cos^2Asin^2A+sin^4A)

=2(cos^4A+sin^4A)

Step-by-step explanation:

3 0
3 years ago
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