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Vikentia [17]
3 years ago
5

In a large population, 69% of the people have been vaccinated. If 5 people are randomly selected, what is the probability that a

t least one of them has been vaccinated?
Mathematics
1 answer:
Darya [45]3 years ago
3 0

Answer: P(x ≥ 1) = 0.997

Step-by-step explanation:

We would assume a binomial distribution for the the people that were sampled. The formula is expressed as

P(x = r) = nCr × p^r × q^(n - r)

Where

x represent the number of successes.

p represents the probability of success.

q = (1 - r) represents the probability of failure.

n represents the number of trials or sample.

From the information given,

p = 69% = 69/100 = 0.69

q = 1 - p = 1 - 0.69

q = 0.31

n = 5

Therefore,

P(x ≥ 1) = 1 - P(x = 0)

P(x = 0) = 5C0 × 0.69^0 × 0.31^(5 - 0) = 0.003

P(x ≥ 1) = 1 - 0.003 = 0.997

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Answer:

x = y + 8

Step-by-step explanation:

Given

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3 years ago
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Bret needs 450 packs of paper for next week. He has 284 packs of paper. How many more packs of paper dose bret need?
gulaghasi [49]

Answer:

166 packs

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Data obtained from the question include:

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A state is considering license plates that have two digits followed by four letters. Assuming no combinations are excluded, how
love history [14]

Answer:

32,292,000

Step-by-step explanation:

In your question, it asks how many license plate combinations we could make WITHOUT repeats.

We need some prior knowledge to answer this question.

We know that:

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  • We can make 10 digits (0 - 9)

With the information we know above, we can solve the question.

Since we CAN'T have repeats, we would be excluding a letter or number for each license plate.

We're going to need to multiply each "section" in order to find how many combinations of license plates we can make.

We decrease by one letter and one number in each section since we can't have repeats.

Now, we can solve.

Work:

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When you're done multiplying, you should get 32,292,000.

This means that there could be 32,292,000 different combinations of license plates.

<h3>I hope this helps you out.</h3><h3>Good luck on your academics.</h3><h3>Have a fantastic day!</h3>
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10

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2+(2x4)

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