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tester [92]
3 years ago
10

Write an equation of the line with the given slope and y-intercept

Mathematics
1 answer:
Ilya [14]3 years ago
3 0

Answer:

The equation of line is y = x + 10

Step-by-step explanation:

Given as :

The slope of line = m = 1

The y intercept of line is 10

Now equation of line in intercept form is y = m x + c

∵ The line have y intercept only then x axis of line is zero

So, The equation of line

 10 = 1 × 0 + c

Or,  10 = 0 + c

So, c = 10

∴ The new equation of line become y = 1 × x + 10

I,,e   y = x + 10

Hence The equation of line is y = x + 10  Answer

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A mountain climber starts a climb at an elevation of 453 feet above sea level. At his first rest stop he has climbed 162 feet, a
Alenkinab [10]

They started at 453, then climbed 162, so now they are at:

453 + 162 = 615 feet.

They then cllmb another 207 feet to get to:

615 + 207 = 822 feet.

They then descend ( climb down) 285 feet.

822 - 285 = 537 feet.

Now they need to get back tot he original 453,

so they have to descend:

537 - 453 = 84 more feet.

The answer is C.

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2 years ago
Solve for B in the picture below
Oxana [17]

Answer:

b= -48

Step-by-step explanation:

by transposing,

43=59+b/3

b/3+59=43

b/3=43-59

b/3= -16

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therefore the answer is b= -48

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2 years ago
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How do I solve this quadratic using the square root property
Nataly [62]

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Step-by-step explanation:

5 0
3 years ago
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On the unit circle, which of the following angles has the terminal point coordinates (√2/2,-√2/2)
aleksandr82 [10.1K]

Answer:

Option B

Step-by-step explanation:

A unit circle means radius of the circle = 1 unit

Let a terminal point on the circle is (x, y) and angle between the point P and x-axis is θ.

Center of the circle is origin (0, 0).

Therefore, ordered pair representing the terminal point will be (OP×Cosθ, OP×Sinθ) = (\frac{\sqrt{2} }{2},-\frac{\sqrt{2} }{2})

OP.Cosθ = 1×Cosθ = \frac{1}{\sqrt{2}}

Cosθ = \frac{1}{\sqrt{2}}

θ = \frac{\pi }{4}+2\pi n,  \frac{7\pi }{4}+2\pi n where n = integers

Similarly, OP×Sinθ = 1×Sinθ = -\frac{1}{\sqrt{2}}

Sinθ = -\frac{1}{\sqrt{2} }

θ = \frac{5\pi }{4}+2\pi n,  \frac{7\pi }{4}+2\pi n where n = integer

Common value of θ will be, θ = \frac{7\pi }{4}

Option B will be the answer.

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3 years ago
I hope that we pass this semester god bless :)) calming it
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Answer:

me too

Step-by-step explanation:

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