Ask question

Ask question

All categories

3 years ago

13

Can someone solve this problem

2 answers:

Rasek [7]3 years ago

7 0

The previous answer isn’t entirely correct. The answer is infinite solutions or all solutions because they equations equal each other at every value

Hoochie [10]3 years ago

5 0

Answer: No Solution

║ 3x + 2y = 7 ==> Multiply by 2
║ 6x + 4y = 14

║ 6x + 4y = 14
║ 6x + 4y = 14

There is no solution.

You might be interested in

Write – 31 +(6+21 - (+31) as a complex number in standard form.

N76 [4]

Answer:

35

Step-by-step explanation:

6 0

4 years ago

Ophia earned $2,000 last month. She used 35 of her earnings to pay her bills. With the remaining money, she bought two shirts fo

Andrej [43]

Sophia has $ 1912.03 left from last month's earnings

<u>Solution:</u>

Given, sophia earned $2,000 last month.

She used 35 of her earnings to pay her bills.

With the remaining money, she bought two shirts for $19.99 each and a pair of earrings for $12.99.

We have to find how much money does Sophia have left from last month's earnings

Now, we know that,

<em>Left money = earned money – used money</em>

= 2000 – (bills paid + 2 shirts cost + 1 pair of ear rings)

= 2000 – (35 + 2 x 19.99 + 12.99)

= 2000 – (35 + 39.98 + 12.99)

= 2000 – (87.97) = 1912.03

Hence, Sophia has $ 1912.03 left with her.

5 0

4 years ago

Use the equation and type the ordered-pairs. y = log 3 x {(1/3, a0), (1, a1), (3, a2), (9, a3), (27, a4), (81, a5)

vagabundo [1.1K]

Answer:

Considering the given equation $y = log_{3}x\\$

And the ordered pairs in the format $(x, y)$

I don't know if it is log of base 3 or 10, but I will assume it is 3.

For $(\frac{1}{3}, a_{0} )$

$x=\frac{1}{3}$

$y=a_{0}$

$y = log_{3}x\\y = log_{3}(\frac{1}{3} )\\y=-\log _3\left(3\right)\\y=-1$

So the ordered pair will be $(\frac{1}{3}, -1 )$

For $(1, a_{1} )$

$x=1$

$y=a_{1}$

$y = log_{3}x\\y = log_{3}1\\y = log_{3}(1)\\Note: \log _a(1)=0\\y = 0$

So the ordered pair will be $(1, 0 )$

For $(3, a_{2} )$

$x=3$

$y=a_{2}$

$y = log_{3}x\\y = log_{3}3\\y = 1$

So the ordered pair will be $(3, 1 )$

For $(9, a_{3} )$

$x=9$

$y=a_{3}$

$y = log_{3}x\\y = log_{3}9\\y=2\log _3\left(3\right)\\y=2$

So the ordered pair will be $(9, 2 )$

For $(27, a_{4} )$

$x=27$

$y=a_{4}$

$y = log_{3}x\\y = log_{3}27\\y=3\log _3\left(3\right)\\y=3$

So the ordered pair will be $(27, 3 )$

For $(81, a_{5} )$

$x=81$

$y=a_{5}$

$y = log_{3}x\\y = log_{3}81\\y=4\log _3\left(3\right)\\y=4$

So the ordered pair will be $(81, 4 )$

4 0

4 years ago

WHAT IS "K" <br> 310 minus (30 times 7) = 5 times k

RSB [31]

Answer:

k = 20

Step-by-step explanation:

310-(30x7) = 5k

310-210=5k

100=5k

/5 /5

20=k

7 0

3 years ago

Sum of (9)<br> Prodect (4)

vekshin1

Answer:

9+(4)

Step-by-step explanation:

3 0

3 years ago