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melamori03 [73]
3 years ago
7

WHAT IS "K" 310 minus (30 times 7) = 5 times k

Mathematics
1 answer:
RSB [31]3 years ago
7 0

Answer:

k = 20

Step-by-step explanation:

310-(30x7) = 5k

310-210=5k

100=5k

 /5   /5

20=k

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Find z1z2 if z1 = 2/5(cos63° + isin63°) and z2 = 10/3(cos117° + isin117°).
Airida [17]

Answer:

-10/3 is the answer

Step-by-step explanation:

Given are two complex numbers as

z1=\frac{2}{5} (cos63  + isin63)\\z2=\frac{10}{3} (cos 117 + isin117})

Recall Demoivre theorem as

(cosA+isinA)(cos A+isin B) = cos(A+B)+isin(A+B)

Hence here we have sum of angles  as

A+B = 63+117 =180

z1z2=\frac{2}{5} \frac{10}{3} (cos180+isin180)

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Since sin180=0 and cos 180=-1

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3 years ago
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Answer:

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3 0
3 years ago
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Yuri [45]
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4 0
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kirza4 [7]
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4 0
3 years ago
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butalik [34]

Answer:

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Step-by-step explanation:

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