Answer:
the amount of matter in the bowling ball remains the same
Explanation:
The reason why the mass of the bowling ball on earth and moon remains the same is that matter in the bowling ball remains the same.
Mass of any substance is the amount of matter it contains.
- Since there is no loss in matter, the mass of the bowling ball anywhere in the universe will be the same.
- Only the weight changes due to differences in gravity.
Answer:
Explanation
we know that
Δ H= m C ΔT
where
ΔH = change in enthalpy (j)
m=mass of the given substance which in this case is water
C= specific heat capacity
ΔT=change in temperature
we know that given mass of water =29.6 g
and ΔT=T2-T1=125-(-55)=180
specific heat capacity of water is 4.18 j/g °C
therefore ΔH= 29.6 g*4.18 j/g °C* 180 °C
so ΔH=22271.04 j
Answer:
Final temperature of solution is 27.48
Explanation:
Total volume of mixture = (60.0+60.0) mL = 120.0 mL
We know, density = (mass)/(volume)
So mass of mixture =
Amount of heat released per mol of =
Where, m represents mass , C represents specific heat, represents change in temperature and n is number of moles
As this reaction is an exothermic reaction therefore temperature of mixture will be higher than it's initial temperature.
Let's say final temperature of mixture is T
So,
Here and
Moles of H_{3}PO_{4} are added = = 0.012 moles
So,
or, T = 27.48
So, final temperature of solution is 27.48
1) Carbon dioxide is a gas, so when is evolved in the reaction, it appears as bubbles. The gas released extinguishes the fire and it can turn lime water milky.
2) When is released in a decomposition reaction we can identify by the strong pungent smell of the gas released.
3) Saturated citric acid can cause corrosion of the metal layers present in the pipes. So, before draining out any acid it is neutralized so that the pipes and other plumbing works do not get damaged leading to leaks in the drainage system.
Answer:
0.689 mg/L Cu
Explanation:
The equation of the best-fit line is:
<em>y</em> = 0.6136<em>x</em> + 0.0142
Where <em>y</em> is the absorbance and <em>x</em> is the concentration in mg/L.
Now using that equation we <u>calculate </u><u><em>x</em></u> when <em>y</em> is equal to 0.438, 0.434 & 0.439.
1) 0.438 = 0.6136<em>x</em> + 0.0142
x = 0.691 mg/L
2) 0.434 = 0.6136<em>x</em> + 0.0142
x = 0.684 mg/L
3) 0.439 = 0.6136<em>x</em> + 0.0142
x = 0.692 mg/L
Finally we <u>calculate the mean of the three concentrations</u>:
- (0.691 + 0.684 + 0.692)/3 = 0.689 mg/L