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Dominik [7]
2 years ago
13

Part b (r)–3-chloro-2-methylhexane will undergo a nucleophilic substitution reaction in the presence of sodium ethoxide and etha

nol. complete the mechanism for the sn2 reaction and draw the products of the reaction. draw all missing reactants and/or products in the appropriate boxes by placing atoms on the grid and connecting them with bonds and including charges where needed. indicate the mechanism by drawing the electron-flow arrows on the molecules. arrows should start on an atom or a bond and should end on an atom, bond, or where a new bond should be created.
Chemistry
1 answer:
arsen [322]2 years ago
8 0

Answer:

See answer below

Explanation:

To understand this, we need to make the reaction involved with the given configuration. Configuration R means that the substituents of the molecule, the priority order goes clockwise (From heaviest to lightest) so, if an Sn2 is ocurring in the reaction this means that the nucleophile, which in this case, is the sodium ethoxide will attack the molecule in the opposite side of the leaving group (which is the chlorine).

Also when this occurs, as Sn2 is a bimolecular reaction and is held in one step, it occurs an inversion in the configuration of the product. So, it's the innitial reactant was R, then the final product will be S.

The mechanism and product can be watched in the attached picture

Hope this helps.

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If a 95.27 mL sample of acetic acid (HC2H3O2) is titrated to the equivalence point with 79.06 mL of 0.113 M KOH, what is the pH
KATRIN_1 [288]

Answer:

8.73

Explanation:

The concentration of acetic acid can be determined as follows:

M_1V_1 = M_2V_2\\(KOH) = (CH_3COOH)

M_{KOH}=0.113 M\\V_{KOH}=79.06 mL

V_{CH_3COOH}=95.27 \\\\M_{CH_3COOH)=?????

M_{CH3COOH} = \frac{M_{KOH}*V_{KOH}}{V_{CH_3COOH}}

M_{CH3COOH} = \frac{0.113*79.06}{95.27}

M_{CH3COOH} = 0.094 M

Moles of CH_3COOH = 95.27* 10^{-3}* 0.094

=0.0090 moles

Moles of  KOH = 79.06*10^{-3}*0.113

= 0.0090 moles

The equation for the reaction can be expressed as :

CH_3COOH     +      KOH     ----->      CH_3COO^{-}K^+      +     H_2O

Concentration of CH_3COO^{- ion = \frac{0.0090}{Total volume (L)}

= \frac{0.0090}{(95.27+79.06)} *1000

= 0.052 M

Hydrolysis of  CH_3COO^{- ion:

CH_3COO^{-      +       H_2O      ----->      CH_3COOH       +     OH^-

K = \frac{K_w}{K_a} = \frac{x*x}{0.052-x}

⇒    \frac{10^{-14}}{1.82*10^{-5}}= \frac{x*x}{0.052-x}

=     0.5494*10^{-9}= \frac{x*x}{0.052-x}

As K is so less, then x appears to be a very infinitesimal small number

0.052-x ≅ x

0.5494*10^{-9}= \frac{x^2}{0.052}

x^2 = 0.5494*10^{-9}*0.052

x^2 = 0.286*10^{-10

x = \sqrt{0.286*10^{-10

x =0.535*10^{-5}M

[OH] = x =0.535*10^{-5}

pOH = -log[OH^-]

pOH = -log[0.535*10^{-5}]

pOH = 5.27

pH = 14 - pOH

pH = 14 - 5.27

pH = 8.73

Hence, the pH of the titration mixture = 8.73

8 0
3 years ago
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natka813 [3]
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7 0
3 years ago
What is the maximum volume of 0.25 M sodium hypochlorite solution (NaOCl, laundry bleach) that can be prepared by dilution of 1.
ehidna [41]

Answer:

0.313L

Explanation:

0.25Mx1.00L=0.80Mx V2

so, 0.25x1.00/0.80=0.313L

8 0
3 years ago
Read 2 more answers
The reaction between carbon tetrachloride, CCl4, and water, H2O, to form carbon dioxide, CO2, and hydrogen chloride, HCl, has a
Ber [7]

Answer:

1) a) It is a slow reaction kinetically.

2) a) It is a catalyst.

3) c) It lowered the activation energy of the reaction.

Explanation:

<em>1) The reaction between carbon tetrachloride, CCl₄, and water, H₂O, to form carbon dioxide, CO₂, and hydrogen chloride, HCl, has a ΔG° value of -232 kJ/mole, and so is thermodynamically favored. But when you mix carbon tetrachloride with water, no change is observed. What is a possible explanation for this? </em>

<em>a) It is a slow reaction kinetically.</em>  TRUE. This is the most likely explanation of why no change is observed.

<em>b) The activation energy of the reaction is too small.</em>  FALSE. Slow reactions have a large activation energy.

<em>c) The reaction is not spontaneous. </em> FALSE. ΔG° < 0 so the reaction is spontaneous.

<em>d)The reaction is not favored thermodynamically.</em> FALSE. ΔG° < 0 so the reaction is favored thermodynamically.

<em>2) What word best describes the role that the palladium plays in the reaction between propene and hydrogen above?</em>

It is a catalyst because it increases the rate of the reaction without being altered by the end of the reaction.

<em>3) What did the palladium do to increase the rate of the reaction between the propene and hydrogen? </em>

<em>a)It changed the thermodynamic equilibrium.</em>  FALSE. Catalysts don't affect equilibrium

<em> b)It made the Gibbs free energy of the reaction more positive.</em>  FALSE. Catalysts don't affect Gibbs free energy.

<em>c)It lowered the activation energy of the reaction.</em>  TRUE. According to the Arrhenius equation, the lower the activation energy, the higher the rate constant, and the higher the rate of reaction. This is how catalysts act.

<em>d)It increased the activation energy of the reaction.</em> FALSE.

7 0
3 years ago
Carbon Dioxide in a 34 L container at a pressure of 387 mm Hg is transferred to a container with a pressure of 274 mm Hg. What i
AVprozaik [17]

Answer:

V2= 0.0796m3

Explanation:

We have that for a real gas the following relation is fulfilled:

PV / T = constant

To use this formula I need to pass the pressure of mmHg to KPa and the volume of L to m3, knowing that

 1Kpa = 7.50062mmHg

1L = 0.001m3

So i can say

P1V1/T1 =P2V2/T2

So

V2= P1V1T2/P2T1

V2= 51.60KPa*0.034m3*350k/36.53KPa*211k

finally

V2= 0.0796m3

7 0
3 years ago
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