Answer:
No for the first one, yes for the second.
Step-by-step explanation:
Plug in the given numbers and see if it works.
15(1) + 3(4) = 10
15 + 12 = 10.
27 ≠ 10
Since 27 does not equal 10, we can already see that solution (1,4) will not work for these equations.
Now for the second problem, do the same thing.
10 = 1 + 9.
This is true, but remember to check the second equation just to be sure.
10 = 4(1) + 6
10 = 4 + 6
This is also true, so it (1,10) is a solution for the second system of equations.
Answer:
a. 80g fish
b. 200g butter
Step-by-step explanation:
a. you have to divide it by 3 because 2 is 1/3 of 6 so 240/3 = 80g of fish.
b. multiply by 2.5 because 15 is 2.5 times 6 so 80*2.5=200g of butter.
Answer:
g(x) has a greater y intercept than f(x)
Step-by-step explanation:
f(x) = 6x^2 + 18x +3
f(0) = 0+0+3
The y intercept is 3
g(x) crosses the y axis at 6
The y intercept is 6
g(x) has a greater y intercept than f(x)
Answer:
v= 6km/h - 1km/h^2 * t
Step-by-step explanation:
From the information, it seems the runner is slowing down because the speed at 1st hour is 5km/h but at 3rd hour becomes 3km/h.
If v= velocity, v0= initial speed, t= time, and the a=acceleration then the function would be:
v= v0 + a * t
To find the acceleration you need to do this equation:
acceleration= velocity1- velocity3 / t3-t1
a = (3km/h-5km/h)/ (3 hour- 1 hour)
a = (-2km/h)/2hour= -1 km/hour^2
After that, you need to find the initial speed. Try to put the 1st-hour variable into the full equation. It would look like this
v= v0 + a * t
5km/h= v0 + (-1 km/hour^2 * 1 hour)
v0= 5km/h + 1km/h
v0= 6km/h
Then the full function would be:
v= 6km/h - 1km/h^2 * t
The graph would look like a backslash(\) from 5 gradually go down to 1.
6
5 O
4 O
3 O
2 O
1 O
1 2 3 4 5
