Based on the distance of the pitcher's mound from the home plate, the path of the ball, and the height the ball was hit, the distance the outfielder threw the ball is C. 183.0 ft.
<h3>How far did the outfielder throw the ball?</h3>
Based on the shape of a mound, the law of cosines can be used.
The distance the ball was thrown by the outfielder can therefore be d.
Distance is:
d² = 60.5² + 226² - (2 x 60.5 x 226 x Cos(39))
d ²= 33,484.42ft
Then find the square root:
d = √33,484.42
= 182.9874
= 183 ft
Find out more solving for distance at brainly.com/question/10739348
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Step-by-step explanation:
you move -5y to the other side.
25=-5y-3xsubtract 25 both sides
0=-5y-3x-25then add 5y both sides
5y=-3x-25divide 5 both sides
y=-3/5x-5
m=-3/5 do rise over runrise/run
b=(0,-5)plot it
3 down and 5 to right or 3 up and 5 left
Answer:
102
Step-by-step explanation:
140-38=102
There is no solution.
Step-by-step explanation:
Given:
y = 2x + 1
4x - 2y = 4
Substitute y = 2x + 1 into 4x - 2y = 4
4x - 2(2x + 1) = 4
4x - 4x - 2 = 4
0x = 4 + 2
0x = 6
Anything to the multiple of zero is zero. Hence 0x = 0, and 0 ≠ 6
So there is no solution to the equation.
You have to take the amount of money payed, which in this case is 45.50, and divide it with 7.
