Oh wait a minute i have to write this down
Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer:
If only Jim purchased a cup of coffee, we will subtract its cost from the total;
9.50 - 1.00 = 8.50
Assuming that the two purchased nothing else for breakfast, and that the cost of an egg scramble was the same for both, let's call the price of the egg scramble x.
Since they both bought eggs, then 2x = 8.50
x = $4.25, the price for each egg scramble
8.5x + 55 = 123
You would use the formula: mx + b = y
The slope is the amount of money each day(mx),and the y-intercept would be the fee(b) and the total cost would be y.