In ∆ ABC and ∆ADC
AB=AD
AC=AC(common side)
BC=DC
So, ∆ABC and ∆ADC are congruent triangles,
so, m<ABC= m<ADC(corresponding angles of the congruent triangles)
x= 97°
Answer:
x = 0.343
Step-by-step explanation:
We want to solve:
5 - 3tan(3x) = 0
such that:
-π< x < π
where π = 3.14
then:
-3.14 < x < 3.14
Let's solve the equation:
5 - 3tan(3x) = 0
-3tan(3x) = -5
tan(3x) = -5/-3 = 5/3
Now we can use the inverse tan function, Atan(x).
Remember that:
Atan( tan(x) ) = tan( Atan(x)) = x
Then if we apply that function to both sides, we get:
Atan( tan(3x)) = Atan(5/3)
3x = Atan(5/3)
x = Atan(5/3)/3 = 0.343
Answer:
|88-x| ≤ 14
Step-by-step explanation:
their score has to be within 14 points of 88.
if their score is above 88, the number will be negative, but the absolute value makes the number positive. if that number is still within 14 of 88, they pass.
if their score is below 88, the number will be negative, and the absolute value keeps the number positive. if that number is still within 14 of 88, they pass.
Answer:
The answer is: A. The area of parallelogram 1 is 4 square units greater than the area of parallelogram 2.
Step-by-step explanation:
Hope this helped :)
Answer:
pizza: $4, coke: $3, chips: $2
Step-by-step explanation:
Lets make the price of a pizza=p a coke= k and a bag of chips=c
then we have the following equations
p+k+c=9
p+2k=10
2p+2c=12
Because p is common in all the equations we shall make it the subject of each equation.
p=9-(k+c)...........i
p=10-2k..............ii
p=6-c...................iii
We then equate i and iii
9-(k+c)=6-c
9-k-c=6-c
putting like terms together we get:
9-6=-c+c+k
1 coke, k=$3
replacing this value in equation ii
we get p=10-2(3)
p=10-6= 4
1 pizza, p=$4
replacing this value in equation iii
4=6-c
c=6-4
=2
a bag of chips, c=$2
Thus, a pizza, a coke and a bag of chips= pizza: $4, coke: $3, chips: $2