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2 years ago

If 24bags of sugar with 21kg. how many bags will weigh 112 kg?

Mathematics

2 answers:

Crank2 years ago

7 0

Answer:128

Step-by-step explanation:

See as follows

21 kg = 24 bags of sugar

1 kg= 24/21= 8/7

Thus,

112 kg= 8/7 × 112=128

Hopefully it helps

Aleks04 [339]2 years ago

3 0

Answer:

128 bags

Step-by-step explanation:

24 bags with 21 kg

128 bags with 112 kg

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Solve negative 8 over 5, the whole multiplied by x minus 6 equals negative 54. A 15

Verdich [7]

-8/5x - 6 = -54....multiply by 5 to get rid of fractions
-8x - 30 = - 270
-8x = -270 + 30
-8x = - 240
x = -240/-8
your answer is 30

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3 years ago

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Please help?!

Anton [14]

Answer:

Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proof is below.

Step-by-step explanation:

Given:

In Δ PQT

PQ = 30 ft

QT = 28 ft

TP = 20 ft

In Δ QRS

QR = 15 ft

RS = 14 ft

SQ = 10 ft

To Prove:

Δ PQT ~ Δ QRS

Proof:

First we consider the ratio of the sides

$\frac{PQ}{QR}=\frac{30}{15} = \frac{2}{1}$ ..............( 1 )

$\frac{QT}{RS}=\frac{28}{14} = \frac{2}{1}$ ..............( 2 )

$\frac{TP}{SQ}=\frac{20}{10} = \frac{2}{1}$ ..............( 3 )

So By equation ( 1 ), ( 2 ) and ( 3 ) we get

$\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}$

Now in Δ PQT and Δ QRS we have

$\frac{PQ}{QR}=\frac{QT}{RS} = \frac{TP}{SQ}$

Which are corresponding sides of a similar triangle in proportion.

∴ Δ PQT ~ Δ QRS .....{S-S-S test for similarity}...Proved

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3 years ago

Yuri thinks that 3/4 is a root of the following function. q(x) = 6x3 + 19x2 – 15x – 28 Explain to Yuri why 3/4 cannot be a root.

k0ka [10]

Answer:

Yuri is not correct.

Step-by-step explanation:

Given expression is q(x) = 6x³ + 19x² - 15x - 28

If 'a' is a root of the given function, then by substituting x = a in the expression, q(a) = 0

Similarly, for x = $\frac{3}{4}$ ,

$q(\frac{3}{4})=6(\frac{3}{4})^3+19(\frac{3}{4})^2-15(\frac{3}{4})-28$

= $6(\frac{27}{64})+19(\frac{9}{16})-15(\frac{3}{4})-28$

= $(\frac{162}{64})+(\frac{171}{16})-(\frac{45}{4})-28$

= $(\frac{162}{64})+(\frac{684}{64})-(\frac{720}{64})-\frac{1792}{64}$

= $-\frac{1666}{64}$

= $-\frac{833}{32}$ ≠ 0

Therefore, Yuri is not correct. x = $\frac{3}{4}$ can not be a root of the given expression.

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3 years ago

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Help with finding g(f(x))<br> f(x) = x squared - 3x + 2 <br> g(x)= x+2

n200080 [17]

Answer:

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Step-by-step explanation:

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The temperature of a liquid in an experiment starts at 0 degrees. The temperature of the liquid changes at a rate of -0.2 per mi

Ilia_Sergeevich [38]

Initial temperature of the liquid = 0 degrees.

Rate of changes of liquid temperature = -0.2 per minute.

Rate of change also represents slope of a linear function.

We know, slope-intercept form of a linear equation

y=mx+b, where m is the slope (rate of change) and b is y-intercept(initial temprature).

With respect to given problem, y represents temperature of a liquid after x number of minutes.

According to given problem, slope(rate of change) = -0.2 per minute and y-intercept(initial temprature)=0.

Plugging values of m and b in the above slope-intercept form of a linear equation.We get,

y=-0.2x+0

or y=-0.2x.

Final temprature is given -14.6 degrees and we need to find time when temprature reach -14.6 degrees.

As y represents temperature of a liquid , we need to plug y=-14.6 in above equation.

We get,

-14.6=-0.2x.

Dividing both sides by -0.2.

-14.6/-0.2=-0.2x/-0.2

x=73.

We got 73 minutes.

73 minutes can be convert in hours.

We have 60 minutes in an hour.

Therefore, 73 = 60+13.

So, 1 hour and 13 minutes will it for the liquid to reach -14.6 degrees.

In minutes answer is 73 minutes.

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2 years ago

If 24bags of sugar with 21kg. how many bags will weigh 112 kg?​

If 24bags of sugar with 21kg. how many bags will weigh 112 kg?