Consider
.. X = {1, 2, 3, 4}, x = 4
.. Y = {2, 3, 4, 5, 6}, y = 5, w = 3
The elements in X or Y (X ∪ Y) are {1, 2, 3, 4, 5, 6}, n = 6.
.. n = 6 = 4 + 5 - 3
Note that if we just add x and y, we count the common elements twice. In order to just count the common elements once, we need to subtract that count from the total of x and y.
selection B is appropriate.
15x^2+21x+6 that’s the answer
Answer:
(x-2)^2 + (y-3)^2 = 4
Step-by-step explanation:
Use the equation (x-h)^2 + (y-k)^2 = r^2 where the center of the circle is (h,k) and the radius is r.
Answer: the equation is
4x^2 + 4x - 12
Step-by-step explanation:
A quadratic equation is an equation in which the highest power of the unknown is 2.
The general form of a quadratic equation is expressed as
ax^2 + bx + c
Where
a is the leading coefficient
c is a constant
Assuming we want to write the quadratic equation in x, from the information given, the roots which are given are -2 and 1 and the leading coefficient is 4.
Therefore, the linear factors of the quadratic equation will be (x+2) and (x-1)
the equation becomes
(x+2)(x-1)
= x^2 - x +2x - 3
= x^2 + x - 3
Given a leading coefficient of 4, we will multiply the quadratic expression by 4. It becomes
4(x^2 + x - 3)
= 4x^2 + 4x - 12
Full question attached
Answer and explanation:
Since x = number of true or false questions correct
And y = number of multiple choice questions correct
And each question for x =2 points
each question for y=3 points
since she then needs a total score of more than 93 to pass, we add up total correct questions and
Inequality equation = 2x +3y >93