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3 years ago

PLS HELP ME W QUESTIONS 9 AND 10

Mathematics

2 answers:

yarga [219]3 years ago

4 0

Answer:

I have done this b4 8: true 9: true 10:false

Step-by-step explanation:

GenaCL600 [577]3 years ago

3 0

Question 8 Answer: True

Question 9 Answer: True

Question 10 Answer: False

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Simplify: 10(-5x+4) A 5x + 4 B - 50x + 4 - 50x + 40 5x + 40

ELEN [110]

Answer:

-50x+40

Step-by-step explanation:

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3 years ago

For which equation is y = 7 a solution?

natali 33 [55]

Answer:

Step-by-step explanation:

11+7=18

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3 years ago

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A cylinder has a volume of 72 cubic inches. What is the volume of a cone with the same height and radius as the cylinder? Show a

nexus9112 [7]

Answer:

24 cubic inches

Step-by-step explanation:

The formulas for the volume of a cylinder and cone are ...

volume of a cylinder = πr^2·h

volume of a cone = (1/3)πr^2·h

For the same radius and height, the cone has 1/3 the volume of the cylinder. Your cone's volume is ...

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4 years ago

Solve the system by using elementary row operations on the equations. Follow the systematic elimination procedure.

Natali5045456 [20]

Answer:

Step-by-step explanation:

The given equation is expressed as

x1 + 2x2 = -24- - - - - - - - --1

x1 + 7x2 = -11- - - - - - - --2

We would eliminate x1 by subtracting equation 2 from equation 1. It becomes

- 5x2 = - 13

Dividing both sides of the equation by - 5, it becomes

- 5x2/- 5 = - 13/- 5

x2 = 13/5

Substituting x2 = 13/5 into equation 2, it becomes

x1 + 7 × 13/5 = -11

x1 + 91/5 = - 11

x1 = - 11 - 91/5

x1 = - 146/5

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3 years ago

Sarah is a computer engineer and manager and works for a software company. She receives a

daser333 [38]

Answer:

a) Number of projects in the first year = 90

b) Earnings in the twelfth year = $116500

Total money earned in 12 years = $969000

Step-by-step explanation:

Given that:

Number of projects done in fourth year = 129

Number of projects done in tenth year = 207

There is a fixed increase every year.

a) To find:

Number of projects done in the first year.

This problem is nothing but a case of arithmetic progression.

Let the first term i.e. number of projects done in first year = $a$

Given that:

$a_4=129\\a_{10}=207$

Formula for $n^{th}$ term of an Arithmetic Progression is given as:

$a_n=a+(n-1)d$

Where $d$ will represent the number of projects increased every year.

and $n$ is the year number.

$a_4=129=a+(4-1)d \\\Rightarrow 129=a+3d .....(1)\\a_{10}=207=a+(10-1)d \\\Rightarrow 207=a+9d .....(2)$

Subtracting (2) from (1):

$78 = 6d\\\Rightarrow d =13$

By equation (1):

$129 =a+3\times 13\\\Rightarrow a =129-39\\\Rightarrow a =90$

Number of projects in the first year = 90

b)

Number of projects in the twelfth year =

$a_{12} = a+11d\\\Rightarrow a_{12} = 90+11\times 13 =233$

Each project pays $500

Earnings in the twelfth year = 233 $\times$ 500 = $116500

Sum of an AP is given as:

$S_n=\dfrac{n}{2}(2a+(n-1)d)\\\Rightarrow S_{12}=\dfrac{12}{2}(2\times 90+(12-1)\times 13)\\\Rightarrow S_{12}=6\times 323\\\Rightarrow S_{12}=1938$

It gives us the total number of projects done in 12 years = 1938

Total money earned in 12 years = 500 $\times$ 1938 = $969000

8 0

3 years ago