1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
RUDIKE [14]
3 years ago
11

the weight M of an object on Mars varies directly as it’s weight E on Earth. A person who weighs 95 lb on Earth weighs 38 lb on

Mars. How much would a 100 lb person weight on Mars
Mathematics
1 answer:
lorasvet [3.4K]3 years ago
8 0

Answer:

A 100 lb person will weight 40 lb on Mars

Step-by-step explanation:

Given:

Weight on Mars directly varies as its weight on earth.

Let weight on Mars be = M

Let weight on Earth be = E

Its known that:

M ∝ E

Thus

M=kE

where k is constant of proportionality.

when  E=95\ lb, then M=38\ lb

thus, we have

38=k(95)

dividing both sides by 95.

\frac{38}{95}=\frac{k(95)}{95}

∴ k=\frac{38}{95}

Thus when E= 100, M would be calculated as

M=\frac{38}{95}\times 100

M=\frac{3800}{95}

∴ M=40\ lb  (Answer)

∴ A 100 lb person will weight 40 lb on Mars.

You might be interested in
What would be the scientific notation of 10,200?
larisa86 [58]
It would be 1.02x10^4
7 0
3 years ago
Read 2 more answers
the sum of 3 decimal numbers is 6. Exactly one of the numbers is less than 1 what could those numbers be.
kati45 [8]
There are infinitely many solutions to this problem (which is why it asks what could those numbers be), so you just have to make one up!

Start with the first sentence.
x + y + z = 6.0

Now one of those numbers has to be less than 1. I'll choose x. And I'll choose a random number, say, 0.7.

0.7 + y + z = 6.0

Now I'll subtract 0.7 from both sides to see what y and z have to add up to.

0.7 + y + z - 0.7 = 6.0 - 0.7
y + z = 5.3

Now I'll choose a random number for y that's less than 5.3.

2.6 + z = 5.3

And subtract 2.6 from both sides to find z.

2.6 + z - 2.6 = 5.3 - 2.6
z = 2.7

And now we have our numbers!
x = <u>0.7</u>
y = <u>2.6</u>
z = <u>2.7</u>
3 0
3 years ago
Topic 9 Review
Lesechka [4]
Merry Christmas and a happy new year
3 0
3 years ago
Please help me with this geometry question, Im pretty sure you need to use SAS congruence rule
Ierofanga [76]

<em>Congruent triangles</em> are two or more triangles with the same length of <u>sides</u> and measure of internal <u>angles</u>. Thus the <em>required</em> proof is as shown below:

From the given diagram, it can be <u>observed</u> that:

AB = AC (<em>similar</em> property of two lines)

AC = AE (<u>similar </u>property of two lines)

Also,

m<A is a <u>common</u> angle to ΔABC and ΔADE

So that it can be <em>concluded </em>that;

ΔABC ≅ ΔADE (Side-Angle-Side property)

Thus since ΔABC ≅ ΔADE are <u>congruent</u>, then;

BC = DE (<u>corresponding</u> sides of <em>congruent</em> triangles)

For further clarifications on congruent triangles, visit: brainly.com/question/1619927

#SPJ1

7 0
2 years ago
25.1° what is the complementary angle
kari74 [83]
90-25.1=64.9 
since complementary angles equal 90
hope this helped
4 0
3 years ago
Other questions:
  • How many times can 4 go in to 66?
    5·2 answers
  • Simplify: −6(1/4 x - 2/3 x + 5/6 x) <br> A) -2 1/2 x <br> B) -x <br> C) 2x <br> D) 3/4 x
    11·1 answer
  • Please help solve the for x. <br> I'm offering 20 points
    12·1 answer
  • What is 26% of $29.50?
    10·2 answers
  • Please send help AsAp​
    9·1 answer
  • The question with the options are in the picture ^ plz and thank you
    6·1 answer
  • I don’t get this Help!!! Plz help ASAP!<br>I’m like ligiterally freaking out rn
    8·2 answers
  • You estimated that there are 18 cats in the neighborhood, but after counting the actual amount was 9 cats. What is the percent e
    15·1 answer
  • Lin knows that there are 4 quarts in a gallon. She wants to convert 6 quarts to a gallon, but cannot decide if she should multip
    5·1 answer
  • Solve this problem.........................
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!