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Bogdan [553]
3 years ago
13

In a appropriate environment, guppies reproduce at an astounding rate. A population of reproducing guppies quadruples every mont

h. How many Guppies will there be after 6 months if the beginning population is only 6 guppies?. a)24,576. b)144. c)46,656. d)1,296.
Mathematics
1 answer:
Marianna [84]3 years ago
3 0
If the guppies multiply by four in six months then that 4 raised to the power of six. Then multiply it with the starting number of guppies which is 6Formula=4^6 (6)4096 x 6= 24576
So, there are 24, 576 guppies in six months. The answer is A.
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3(x - 5) – 3 = 5(x - 2) + 2x
Arlecino [84]

Answer:

x=−2

Step-by-step explanation:       Step 1: Simplify both sides of the equation.

3(x−5)−3=5(x−2)+2x

(3)(x)+(3)(−5)+−3=(5)(x)+(5)(−2)+2x(Distribute)

3x+−15+−3=5x+−10+2x

(3x)+(−15+−3)=(5x+2x)+(−10)(Combine Like Terms)

3x+−18=7x+−10

3x−18=7x−10

Step 2: Subtract 7x from both sides.

3x−18−7x=7x−10−7x

−4x−18=−10

Step 3: Add 18 to both sides.

−4x−18+18=−10+18

−4x=8

Step 4: Divide both sides by -4.

−4x

−4

=

8

−4

x=−2

6 0
3 years ago
To win a state "A" lottery, one must correctly select 5 numbers from a collection of 50 numbers (1 through 50). The order in whi
love history [14]
The number of possibilities for the first one is 50 choose 5, and the number of possibilities for the second one is 60 choose 6. Since 50 choose 5 is 2118760 and 60 choose 6 is 50063860. There are less possible outcomes for state "A" and therefore you have a higher chance of winning.
3 0
3 years ago
The telephone operator has told Jed to deposit $.60 in how many ways can he do this using nickels dimes and quarters
romanna [79]
6 dimes, 12 nickles, 2 quarters and 2 nickles and 2 quarters and a dime.

There are many ways to do this.
4 0
3 years ago
Read 2 more answers
Let w = x2 + y2 + z2, x = uv, y = u cos(v), z = u sin(v). use the chain rule to find ∂w ∂u when (u, v) = (9, 0).
jasenka [17]
By the chain rule,

\dfrac{\partial w}{\partial u}=\dfrac{\partial w}{\partial x}\cdot\dfrac{\partial x}{\partial u}+\dfrac{\partial w}{\partial y}\cdot\dfrac{\partial y}{\partial u}+\dfrac{\partial w}{\partial z}\cdot\dfrac{\partial z}{\partial u}
\dfrac{\partial w}{\partial u}=2xv+2y\cos v+2z\sin v

We also have x(9,0)=0, y(9,0)=9, and z(9,0)=0, so at this point we get

\dfrac{\partial w}{\partial u}(9,0)=2\cdot9\cdot\cos0=18
7 0
4 years ago
This figure is a square, with side lengths as shown.
Olin [163]

The perimeter and area of the square are 16√5 mm and 80 mm²

<h3 /><h3>How to find perimeter and area of a square?</h3>

Perimeter of a square = 4L

where

  • l = length

Therefore,

Perimeter of a square = 4 × 4√5

Perimeter of a square = 16√5 mm

Area of a square = l²

Area of a square = (4√5)²

Area of a square = 16 × 5

Area of a square = 80 mm²

learn more on square here: brainly.com/question/14090908

#SPJ1

4 0
2 years ago
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