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liubo4ka [24]
3 years ago
5

A female executive selecting her wardrobe purchased three blazers, two blouses, and five skirts in coordinating colors. how many

ensembles consisting of a blazer, a blouse, and a skirt can she create from this collection?
Mathematics
1 answer:
Ainat [17]3 years ago
7 0
She  can make a total of 30 different outfits, just multiply them all together.
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The amount Lin's sister earns at her part-time job is proportional to the number
gulaghasi [49]

Answer:

y = 9.6x

Yes, y is a function of x.

x =  \frac{5}{48} y

Step-by-step explanation:

For a proportional relation, the equation is given by:

y = kx

where k is the unit rate of change.

We were told that, Lin's sister earns $9.6 per hour.

This means k=9.6.

We substitute to get:

y = 9.6x

We could rewrite this as

y(x) = 9.6x

Yes, y is a function of x.

To obtain an equation describing x as a function of y, we solve for x to get:

x =  \frac{1}{9.6} y

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Dalia has 9 hamsters and 4 fish at her house. Write the ratio of fish to the total number of pets in two different ways (watch w
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A. 4:13, 4 to 13

Step-by-step explanation:

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Answer:

A

Step-by-step explanation:

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05.06)Which net represents the pyramid below? The image of a square pyramid. A hexagon with a triangle connected with a dotted l
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Answer:

A square with a triangle connected to each side with a dotted line.

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Construct the confidence interval for the population mean mu. c = 0.90​, x = 16.9​, s = 9.0​, and n = 45. A 90​% confidence inte
Georgia [21]

Answer:

The  90%  confidence interval for population mean is   14.7  <  \mu  <  19.1

Step-by-step explanation:

From the question we are told that

   The sample mean is  \= x  =  16.9

    The confidence level is  C  =  0.90

     The sample size is  n  =  45

     The standard deviation

Now given that the confidence level is  0.90 the  level of significance is mathematically evaluated as

       \alpha =  1-0.90

       \alpha  =  0.10

Next we obtain the critical value of  \frac{\alpha }{2}  from the standardized normal distribution table. The values is  Z_{\frac{\alpha }{2} } =  1.645

The  reason we are obtaining critical values for \frac{\alpha }{2}  instead of  that of  \alpha  is because \alpha  represents the area under the normal curve where the confidence level 1 - \alpha (90%)  did not cover which include both the left and right tail while \frac{\alpha }{2}  is just considering the area of one tail which is what we required calculate the margin of error

  Generally the margin of error is mathematically evaluated as

        MOE  =  Z_{\frac{\alpha }{2} } *  \frac{\sigma }{\sqrt{n} }

substituting values

         MOE  = 1.645*  \frac{ 9 }{\sqrt{45} }

         MOE  = 2.207

The  90%  confidence level interval is mathematically represented as

      \= x  -  MOE  <  \mu  <  \= x  +  MOE

substituting values

     16.9 -  2.207  <  \mu  <  16.9 +  2.207

    16.9 -  2.207  <  \mu  <  16.9 +  2.207

     14.7  <  \mu  <  19.1

         

3 0
3 years ago
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