<h3>
Answer: 144</h3><h3>
Step-by-step explanation:</h3><h3 />
Since, the first 9 multiple of 4 starts from 0 are,
0, 4, 8, 12, 16, 20, ................
Which is an AP,
Having the first term, 
And, the successive difference, d = 4,
Since, the sum of the n term of an AP,
![S_n = \frac{n}{2}[2a + (n-1)d]](https://tex.z-dn.net/?f=S_n%20%3D%20%5Cfrac%7Bn%7D%7B2%7D%5B2a%20%2B%20%28n-1%29d%5D)
Hence the sum of 9 term of the above AP,
![S_9 = \frac{9}{2}[2\times 0 + (9-1)\times 4]](https://tex.z-dn.net/?f=S_9%20%3D%20%5Cfrac%7B9%7D%7B2%7D%5B2%5Ctimes%200%20%2B%20%289-1%29%5Ctimes%204%5D)



The midpoint lines are half the opposite side length.
Line DE is given as 7 , So Line F = 7 x 2 = 14
Line EF is given as 12, so Line D = 12 x 2 = 24
Line DF is given as 16, so line E = 16 x 2 = 32
The perimeter is the sum of the 3 sides:
Perimeter = 14 + 24 + 32 = 70
Hello guys I am new here and I don't know how to answer your question
Answer:
QR = 1.3
Step-by-step explanation:
Sides TQ and TS are congruent, thus Δ QST is isosceles.
RT is a perpendicular bisector, that is it bisects QS at right angles, thus
QR = RS = 1.3