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Julli [10]
4 years ago
7

Help needed plz correct answer gets Brainlest

Mathematics
1 answer:
bogdanovich [222]4 years ago
7 0

Answer:

Find a common denominator on the right side of the equation.

Step-by-step explanation:

On the right side of the equation we began with

-\frac{c}{a} +\frac{b^2}{4a^2}

Then we ended with

-\frac{4ac}{4a^2} +\frac{b^2}{4a^2}

As we can see, only the left term changed. It was multiplied by \frac{4a}{4a}. This was done in order to match the denominator of the right term.

As you can see they now match.

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a school netball team won ten matches , lost four and drew 1/8 of the total played . how many matches were drawn and what fracti
defon

The school net ball team drew 2 matches. The team won \frac{5}{8} of total matches played

<h3><u>Solution:</u></h3>

Given, A school netball team won ten matches, lost four and drew \frac{1}{8} of the total played

Let the total number of matches played be "n"

Number of matches drawn = \frac{1}{8} of n

<em>Total matches played = number of won matches + number of lost matches + number of drawn matches</em>

\begin{array}{l}{n=10+4+\frac{1}{8} n} \\\\ {n-\frac{1}{8} n=10+4}\end{array}

Taking "n" as common from left hand side,

\begin{array}{l}{\mathrm{n}\left(1-\frac{1}{8}\right)=14} \\\\ {\mathrm{n} \times \frac{8-1}{8} \quad 14} \\\\ {\mathrm{n} \times \frac{7}{8}=14} \\\\ {\mathrm{n}=16}\end{array}

So, they played 16 matches in total

Number of matches drawn = \frac{1}{8} of n = \frac{1}{8} \times 16 = 2\text { Fraction of won matches }=\frac{\text { number of matches won }}{\text { number of matches played }}=\frac{10}{16}=\frac{5}{8}

\text { Hence, the team drew } 2 \text { matches and won } \frac{5}{8} \text { of total played matches. }

3 0
3 years ago
Need help don’t know what I’m doing
docker41 [41]
This problem mean you have to find the point that the Domain and Range is suit (I'm sorry English is my second language) 
Example:
1) G ; 2) Y
If you want me to do the rest of it tell me Okay ^^

8 0
3 years ago
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