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ludmilkaskok [199]
3 years ago
15

Taylor has a $30.00 gift card that she can

Mathematics
2 answers:
WITCHER [35]3 years ago
8 0

Answer:

7 journals

Step-b7 y-step explanation:

In this question, we have to find how many journals she can buy with her left over money.

We know that she has a $30 gift card. We also know that she already spent $9 of it on a frame.

With this knowledge, we know that she has $21 left on her gift card.

To find how many journals she can buy, lets set up an equation where x = the amount of journals.

3x = 21

Solve for x:

3x = 21

Divide both sides by 3

x = 7

This means that she could buy 7 journals.

Debora [2.8K]3 years ago
4 0

Answer:

She can buy 7 Journals

Step-by-step explanation:

9 + 3x ≤ 30

Subtract 9 on both sides...

3x ≤ 21

Divide by 3 on both sides...

x ≤ 7

Hope this helps :)

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A. f(x) = l-2xl - 3<br> Domain: {1, 2, 3}<br> Find the range
gizmo_the_mogwai [7]

Hello there!

We are given the function:

\displaystyle \large{ f(x) =  | - 2x|  - 3} \\

To find the range, we know that domain is the set of all x-values and also called 'input' while range is the set of all y-values and also called 'output'.

Basic Function - you add the input, you get the output. You add x-value in a function, you get y-value. You add domain, you get range.

So, we substitute x = 1,2 and 3 in the function.

<u>x</u><u> </u><u>=</u><u> </u><u>1</u>

\displaystyle \large{ f(1) =  | - 2(1)|  - 3} \\   \displaystyle \large{ f(1) =  | - 2|  - 3} \\

Recall that any numbers in absolute value are always positive.

\displaystyle \large{ f(1) =  2 - 3} \\   \displaystyle \large{ f(1) =   - 1} \\

<u>x</u><u> </u><u>=</u><u> </u><u>2</u>

\displaystyle \large{ f(2) =  | - 2(2)|  - 3} \\   \displaystyle \large{ f(2) =  | - 4 |   - 3} \\   \displaystyle \large{ f(2) =  4 - 3} \\   \displaystyle \large{ f(2) =  1}

<u>x</u><u> </u><u>=</u><u> </u><u>3</u>

\displaystyle \large{ f(3) =  | - 2(3)|  - 3} \\   \displaystyle \large{ f(3) =  | - 6|   - 3} \\   \displaystyle \large{ f(3) =  6 - 3} \\   \displaystyle \large{ f(3) =  3}

Therefore, Range: {-1,1,3}

Let me know if you have any questions!

Topic: Absolute Value Function / Modulus Function

6 0
3 years ago
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