Answer: The interquartile range is preferred when the data are skewed or have outliers. An advantage of the standard deviation is that it uses all the observations in its computation.
Step-by-step explanation:
The interquartile range are resistant to outliers and can be used for data having glaring outliers.
Outliers are values that are too far away from the central value.
Interquartile range is a better option than standard deviation when there are a few extreme values and the distribution is skwed.
1834 bfc I believe that’s the right answer
Year rank population
1790 3 18320
1800 4 24937
1810 4 33787
1820 4 43298
1830 4 61392
1840 5 93383
1850 3 136881
1860 5 177840
1870 7 250526
1880 5 362839
1890 6 448477
1900 5 560892
1910 5 670585
1920 7 748060
1930 9 781188
1940 9 770816
1950 10 801444
1960 13 697197
1970 16 641071
1980 20 562994
1990 20 574283
Answer: A
Step-by-step explanation: Because I got it wrong and it said it said it was A
we know that
arithematic sequence will always have common difference
(a)
−5, −7, −10, −14, −19, …
we can see that
![d_1=-7+5=-2](https://tex.z-dn.net/?f=%20d_1%3D-7%2B5%3D-2%20)
![d_2=-10+7=-3](https://tex.z-dn.net/?f=%20d_2%3D-10%2B7%3D-3%20)
they are not equal
so, this is not arithematic sequence
(2)
1.5, −1.5, 1.5, −1.5, …
we can see that
![d_1=-1.5-1.5=-3](https://tex.z-dn.net/?f=%20d_1%3D-1.5-1.5%3D-3%20)
![d_2=1.5+1.5=3](https://tex.z-dn.net/?f=%20d_2%3D1.5%2B1.5%3D3%20)
they are not equal
so, this is not arithematic sequence
(3)
4.1, 5.1, 6.2, 7.2, …
we can see that
![d_1=5.1-4.1=1](https://tex.z-dn.net/?f=%20d_1%3D5.1-4.1%3D1%20)
![d_2=6.2+5.1=1.1](https://tex.z-dn.net/?f=%20d_2%3D6.2%2B5.1%3D1.1%20)
they are not equal
so, this is not arithematic sequence
(4)
−1.5, −1, −0.5, 0, …
we can see that
![d_1=-1+1.5=0.5](https://tex.z-dn.net/?f=%20d_1%3D-1%2B1.5%3D0.5%20)
![d_2=-0.5+1=0.5](https://tex.z-dn.net/?f=%20d_2%3D-0.5%2B1%3D0.5%20)
they are equal
so, this is arithematic sequence