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lozanna [386]
3 years ago
15

What perfect square goes into the square root of 108

Mathematics
2 answers:
Vesna [10]3 years ago
8 0
We can rewrite 27 as 9 × 3, where 9 is a perfect square, then take it through our steps. Since 3 doesn't have any perfect square factors, √(3) is as simplified as possible, so we have that the square root of 108 in radical form is 6 × √(3), or 6√(3).
Leona [35]3 years ago
6 0

Answer:

6\sqrt{3}

Step-by-step explanation:

so we are going to create a factor tree which is the .The factor tree is any two numbers that equal to 108.

next we are going to pull out our pairs.so there are one pair of two's and one pair of threes

\sqrt[2]{108} =2*3\sqrt{3} =6\sqrt{3}

pls mark me brainliest

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1) A family consisting of three persons—A, B, and C—goes to a medical clinic that always has a doctor at each of stations 1, 2,
crimeas [40]

Answer:

Step-by-step explanation:

Let us record the station number 1, 2 or 3 for each family member A, B or C.

I am attaching a table containing total outcomes. Outcomes are presented along rows while the assigned station to each member is written along columns. For ease of understanding, 1 3 2 in the table should be interpreted as family member A being assigned to station 1, member B to station 3 and member C to station number 2, respectively.

From table it is clear that the total outcomes possible are 27.

We know that, probability can be defined as,

PROBABITILY = \frac{NUMBER\;OF\;DESIRED\;OUTCOMES}{TOTAL\;NUMBER\;OF\;OUTCOMES}

a) All Members Assigned to the Same Station.

Cases for all members being assigned to same station are as follows:

[1 1 1], [2 2 2], [3 3 3] (outcome number 1, 14 and 27 in the table).

Therefore,

PROBABILITY\;(Case\;a) = \frac{3}{27}\\\\PROBABILITY\;(Case\;a) = 0.111

b) At Most Two Members Assigned to the Same Station.

It means that maximum of 2 members can have the same station. Cases for this situation are as follows:

[1 1 2], [1 1 3], [1 2 1], [1 2 2], [1 3 1], [1 3 3], [2 1 1], [2 1 2], [2 2 1], [2 2 3], [2 3 2],

[2 3 3], [3 1 1], [3 1 3], [3 2 2], [3 2 3], [3 3 1], [3 3 2]

(outcome number 2, 3, 4, 5, 7, 9, 10, 11, 13, 15, 17, 18, 19, 21, 23, 24, 25 and 26 in the table).

Therefore,

PROBABILITY\;(Case\;b) = \frac{18}{27}\\\\PROBABILITY\;(Case\;b) = 0.666

c) All Members Assigned to a Different Station.

For this scenario, we have the following results:

[1 2 3], [1 3 2], [2 1 3], [2 3 1], [3 1 2], [3 2 1] (outcome number 6, 8, 12, 16, 20 and 22 in the table).

Therefore,

PROBABILITY\;(Case\;c) = \frac{6}{27}\\\\PROBABILITY\;(Case\;c) = 0.222

3 0
3 years ago
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antoniya [11.8K]
The 0 in the number 402 is in the ten place. The number after it is 2. 2 is less than 5.

402 rounded to the nearest ten is 400

The 4 in the number 402 is in the hundreds place. The number after it is 0. 0 is less than 5.

402 rounded to the nearest hundred is 400
6 0
3 years ago
Last year, there were 380 students at woodland middle school. This year, the student population will increase by 5%. What will b
olga_2 [115]
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3 years ago
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Jet001 [13]

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Step-by-step explanation:

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3 0
2 years ago
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makvit [3.9K]

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Similarly to the previous exercise, P(A∩B) is the probability that a customer order a large hot drink. So, P(A∩B) = 22/100 = 0.22

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multiplying by 100%, we obtain 81.4%

8 0
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