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lozanna [386]
4 years ago
15

What perfect square goes into the square root of 108

Mathematics
2 answers:
Vesna [10]4 years ago
8 0
We can rewrite 27 as 9 × 3, where 9 is a perfect square, then take it through our steps. Since 3 doesn't have any perfect square factors, √(3) is as simplified as possible, so we have that the square root of 108 in radical form is 6 × √(3), or 6√(3).
Leona [35]4 years ago
6 0

Answer:

6\sqrt{3}

Step-by-step explanation:

so we are going to create a factor tree which is the .The factor tree is any two numbers that equal to 108.

next we are going to pull out our pairs.so there are one pair of two's and one pair of threes

\sqrt[2]{108} =2*3\sqrt{3} =6\sqrt{3}

pls mark me brainliest

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Answer:

A

Step-by-step explanation:

Recall that for a quadratic equation of the form:

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The number of solutions it has can be determined using its discriminant:  

\Delta = b^2-4ac

Where:

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  • And if the discriminant is zero, we have exactly one solution.

We have the equation:

2x^2+5x-k=0

Thus, <em>a</em> = 2, <em>b</em> = 5, and <em>c</em> = -<em>k</em>.

In order for the equation to have exactly one distinct solution, the discriminant must equal zero. Hence:

b^2-4ac=0

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Solve:

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3 0
3 years ago
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Step-by-step explanation:

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