What are you solving for? if you are solving for x, then x=(P-12)/(Q-13)
Answer:
1/4
Step-by-step explanation:
Answer:
P(O and O) =0.1296
P=0.3778
Step-by-step explanation:
Given that
blood phenotypes in a particular population
A=0.48
B=0.13
AB=0.03
O=0.36
As we know that when A and B both are independent that
P(A and B)= P(A) X P(B)
The probability that both phenotypes O are in independent:
P(O and O)= P(O) X P(O)
P(O and O)= 0.36 X 0.36 =0.1296
P(O and O) =0.1296
The probability that the phenotypes of two randomly selected individuals match:
Here four case are possible
So
P=P(A and A)+P(B and B)+P(AB and AB)+P(O and O)
P=0.48 x 0.48 + 0.13 x 0.13 + 0.03 x 0.03 + 0.36 x 0.36
P=0.3778
<span>-6x - 2 = 40
-6x = 42
x = -7
..................</span>
Answer:
9x^4+21x+6=0
Step-by-step explanation:
( 3x^2)^2+7(3x +2) -8=0
((3^2)*(x^2)^2)+(7*3x)+(7*2)-8=0
9(x^4)+21x+14-8=0
9x^4+21x+6=0