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3 years ago

What is the value of -2/5 / 3/4?

Mathematics

1 answer:

Sveta_85 [38]3 years ago

7 0

Answer:

-8/15

Step-by-step explanation:

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60.2 rounded to the nearest hundredth

Anna11 [10]

It’s gunna be 60.2 I believe

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3 years ago

Shane buys fishing line in rolls of 700 yards of line per roll. How many feet of fishing line are in one roll?

Vesna [10]

The answer is 2,100. since there are 3 feet in 1 yard, you would multiple 700 by 3.

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3 years ago

Which expression is equivalent to (xy2x−3y)4?

lianna [129]

Answer:

4x2y2−12y

Step-by-step explanation:

Write the problem as a mathematical expression. ( x y 2 x − 3 y ) ⋅ 4 Multiply x by x by adding the exponents. ( x 2 y 2 − 3 y ) ⋅ 4 Simplify by multiplying through. 4 ⋅ ( x 2 y 2 ) − 12 y Remove parentheses. 4 x 2 y 2 − 12 y

6 0

2 years ago

534×417 show your work

andre [41]

Answer:

222,678

Step-by-step explanation:

8 0

3 years ago

A lot of 25 skylight covers are received at your construction site, and before installation are subjected to an acceptance testi

8090 [49]

Answer:

If the lot has 4 defective covers out of 25 total covers, the probability of accepting the lot is P=0.98.

Step-by-step explanation:

We have a population of N=25 skylight covers, were K=4 are defective.

We sample n=5 covers, and we will accept the lot if k=2 or fewer are defective.

We will use the hypergeometric distribution to model this probabilities.

First, to be accepted, the sample can have 2, 1 or 0 defective covers, so the probability of being accepted is:

$P(accepted)=P(k\leq2)=P(k=0)+P(k=1)+P(k=2)$

The probability that there are k defective covers in the sample is:

$P(k)=\dfrac{\dbinom{k}{k}\dbinom{N-k}{n-k}}{\dbinom{N}{n}}$

Then, we can calculate the individual probabilities as:

$P(k=0)=\dfrac{\dbinom{4}{0}\cdot \dbinom{25-4}{5-0}}{\dbinom{25}{5}}=\dfrac{\dbinom{4}{0}\cdot \dbinom{21}{5}}{\dbinom{25}{5}}\\\\\\P(k=0)=\dfrac{1\cdot 20349}{53130}=0.38$

$P(k=1)=\dfrac{\dbinom{4}{1}\cdot \dbinom{25-4}{5-1}}{\dbinom{25}{5}}=\dfrac{\dbinom{4}{1}\cdot \dbinom{21}{4}}{\dbinom{25}{5}}\\\\\\P(k=1)=\dfrac{4\cdot 5985}{53130}=0.45$

$P(k=2)=\dfrac{\dbinom{4}{2}\cdot \dbinom{25-4}{5-2}}{\dbinom{25}{5}}=\dfrac{\dbinom{4}{2}\cdot \dbinom{21}{3}}{\dbinom{25}{5}}\\\\\\P(k=2)=\dfrac{6\cdot 1330}{53130}=0.15$

If we add this probabilities, we have:

$P(accepted)=P(k\leq2)=P(k=0)+P(k=1)+P(k=2)\\\\P(accepted)=0.38+0.45+0.15=0.98$

If the lot has 4 defective covers out of 25 total covers, the probability of accepting the lot is P=0.98.

6 0

3 years ago