All categories

3 years ago

A child is building a triangular tower. The first (bottom) row of the 12-row tower is made with 12 blocks. Each successive row

Mathematics

2 answers:

likoan [24]3 years ago

6 0

i have answered this question before let me post an image

qaws [65]3 years ago

6 0

Answer:

It's the 1st option

Step-by-step explanation:

You might be interested in

Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?

sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have $V=IR^{2}$ and let $H$ be the subset of $V$ of all points on the line

$4x+3y=12$

We need to find if $H$ is a subspace of the vector space $V$ .

In $IR^{2}$ all the possibilities for own subspace of the vector space $IR^{2}$ are :

$IR^{2}$ itself.

The vector $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$

All lines in $IR^{2}$ that passes through the origin ( $0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]$ )

We know that $H$ is the subset of $IR^{2}$ of all points on the line $4x+3y=12$

If we look at the equation, the point $\left[\begin{array}{c}0&0\end{array}\right]$ doesn't verify it because :

$4x+3y=12\\4(0)+3(0)=12\\0=12$

Which is an absurd. Therefore, $H$ doesn't contain the origin (and $H$ is a line in $IR^{2}$ ). Finally, it can't be a vector space of $V=IR^{2}$

8 0

3 years ago

Find the length of UC on the attached diagram. Thank you!

ValentinkaMS [17]

<h2>Answer </h2>

The length of UC is 18

<h2>Explanation </h2>

First we are going to find the length of JN; then we are subtracting from it the length of JU plus the length of CN.

We can infer from our picture that JN is 82 + 105, so JN = 187

We can also infer that JU = JH + HU

JU = 22 + 96

JU = 118

We can also infer that CN = 51

Now we can fin the length of UC:

$UC=JN-(JU+CN)$

$UC=187-(118+51)$

$UC=18$

We can conclude that the length of UC is 18.

3 0

3 years ago

Read 2 more answers

find the local and/or absolute extrema for the function over the specified domain. (Order your answers from smallest to largest

Arlecino [84]

Answer:

Minimum 8 at x=0, Maximum value: 24 at x=4

Step-by-step explanation:

Retrieving data from the original question:

$f(x)=x^{2}+8\:over\:[-1,4]$

1) Calculating the first derivative

$f'(x)=2x$

2) Now, let's work to find the critical points

Set this

$2x=0\\x=0$

0, belongs to the interval. Plug it in the original function

$f(0)=(0)^2+8\\f(0)=8$

3) Making a table x, f(x) then compare

x| f(x)

-1 | f(-1)=9

0 | f(0)=8 Minimum

4 | f(4)=24 Maximum

4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.

5 0

3 years ago

Given f(x)=4x+5 and g(x)= x^2+x; find (f∘g)(-5)<br> Please show all steps thank you

Greeley [361]

Answer:

$(f\circ g)(-5)=85$

Step-by-step explanation:

We are given:

$\displaystyle f(x)=4x+5\text{ and } g(x)=x^2+x$

And we want to find:

$(f\circ g)(-5)$

This is equivalent to:

$\displaystyle =f(g(-5))$

So, we will evaluate g(-5) first, which yields:

$\displaystyle g(-5)=(-5)^2+(-5)=25-5=20$

So:

$=f(g(-5))=f(20)$

Then:

$\displaystyle f(20)=4(20)+5=80+5=85$

Therefore:

$(f\circ g)(-5)=85$

6 0

3 years ago

The product of the first 3 positive whole numbers

Kryger [21]

Answer:

If you mean by 1*2*3=6

Step-by-step explanation:

3 0

3 years ago