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Nuetrik [128]
3 years ago
6

A child is building a triangular tower. The first (bottom) row of the 12-row tower is made with 12 blocks. Each successive row

Mathematics
2 answers:
likoan [24]3 years ago
6 0

i have answered this question before let me post an image

qaws [65]3 years ago
6 0

Answer:

It's the 1st option

Step-by-step explanation:

You might be interested in
Let V=ℝ2 and let H be the subset of V of all points on the line 4x+3y=12. Is H a subspace of the vector space V?
sergejj [24]

Answer:

No, it isn't.

Step-by-step explanation:

We have V=IR^{2} and let H be the subset of V of all points on the line

4x+3y=12

We need to find if H is a subspace of the vector space V.

In IR^{2} all the possibilities for own subspace of the vector space IR^{2} are :

  • IR^{2} itself.
  • The vector 0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]
  • All lines in IR^{2} that passes through the origin  (  0_{IR^{2}}=\left[\begin{array}{c}0&0\end{array}\right]  )

We know that H is the subset of IR^{2} of all points on the line 4x+3y=12

If we look at the equation, the point \left[\begin{array}{c}0&0\end{array}\right] doesn't verify it because :

4x+3y=12\\4(0)+3(0)=12\\0=12

Which is an absurd. Therefore, H doesn't contain the origin (and H is a line in IR^{2}). Finally, it can't be a vector space of V=IR^{2}

8 0
3 years ago
Find the length of UC on the attached diagram. Thank you!
ValentinkaMS [17]
<h2>Answer </h2>

The length of UC is 18

<h2>Explanation </h2>

First we are going to find the length of JN; then we are subtracting from it the length of JU plus the length of CN.

We can infer from our picture that JN is 82 + 105, so JN = 187

We can also infer that JU = JH + HU

                                     JU = 22 + 96

                                     JU = 118

We can also infer that CN = 51

Now we can fin the length of UC:

UC=JN-(JU+CN)

UC=187-(118+51)

UC=18

We can conclude that the length of UC is 18.

3 0
3 years ago
Read 2 more answers
find the local and/or absolute extrema for the function over the specified domain. (Order your answers from smallest to largest
Arlecino [84]

Answer:

Minimum 8 at x=0, Maximum value: 24 at x=4

Step-by-step explanation:

Retrieving data from the original question:

f(x)=x^{2}+8\:over\:[-1,4]

1) Calculating the first derivative

f'(x)=2x

2) Now, let's work to find the critical points

Set this

2x=0\\x=0    

0, belongs to the interval. Plug it in the original function

f(0)=(0)^2+8\\f(0)=8

3)  Making a table x, f(x) then compare

x|  f(x)

-1 | f(-1)=9  

0 | f(0)=8   Minimum

4 | f(4)=24 Maximum

4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.    

5 0
3 years ago
Given f(x)=4x+5 and g(x)= x^2+x; find (f∘g)(-5)<br> Please show all steps thank you
Greeley [361]

Answer:

(f\circ g)(-5)=85

Step-by-step explanation:

We are given:

\displaystyle f(x)=4x+5\text{ and } g(x)=x^2+x

And we want to find:

(f\circ g)(-5)

This is equivalent to:

\displaystyle =f(g(-5))

So, we will evaluate g(-5) first, which yields:

\displaystyle g(-5)=(-5)^2+(-5)=25-5=20

So:

=f(g(-5))=f(20)

Then:

\displaystyle f(20)=4(20)+5=80+5=85

Therefore:

(f\circ g)(-5)=85

6 0
3 years ago
The product of the first 3 positive whole numbers
Kryger [21]

Answer:

If you mean by 1*2*3=6

Step-by-step explanation:

3 0
3 years ago
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