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Rasek [7]
3 years ago
7

What is y= -3/2x + 4 in standard form

Mathematics
1 answer:
Vitek1552 [10]3 years ago
8 0

Answer:

2y + 3x = 8

Step-by-step explanation:

<u>Step 1:  Add 3/2x to both sides</u>

y + 3/2x = -3/2x + 4 + 3/2x

y + 3/2x = 4

<u>Step 2:  Multiply both sides by 2</u>

(y + 3/2x)*2 = 4*2

2y + 3x = 8

Answer:  2y + 3x = 8

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A line passes through the points (3,0) and (4,2). What is its equation in slope-intercept form?
N76 [4]

Answer:

y = 2x - 6

Step-by-step explanation:

<h2>Slope intercept form:</h2>

     Equation of the line:

            \sf \boxed{ y = mx  +b}

      Here m is the slope and b is the y-intercept.

Step 1:  Find the slope

       (3 , 0) ⇒ x₁ = 3  & y₁ = 0

       (4 , 2) ⇒ x₂ = 4  &  y₂ = 2

      \sf \boxed{Slope=\dfrac{y_2-y_1}{x_2-x_1}}

                \sf = \dfrac{2 -0}{4-3}\\\\= \dfrac{2}{1}\\\\=2

<h3>      m = 2</h3>

Step2: Now, substitute the value of 'm' in the equation.

    y = 2x + b

Step3: In the above equation plug in any point. Here, (3 ,0) is chosed.

      0 = 2*3 + b

      0 = 6 + b

      -6 = b

<h3>      b = -6</h3>

Step4: Equation of the line:

<h3>           y = 2x - 6</h3>

3 0
2 years ago
Help due soon plz helpp
dolphi86 [110]

Answer: <em>7) -12;</em>

<em>                8) 0 или 1.</em>

Step-by-step explanation:

<em>7.</em>

<em>x ≤ - 12</em>

<em>x ∈ ( - ∞; - 12]</em>

<em>Наибольшее целое значение, при котором верно неравенство равно </em><em>-12.</em>

<em></em>

<em>8.</em>

<em>-9,6</em><em>*</em><em>8 > - 9,627</em>

<em>Варианты возможных чисел: -9,618 и -9,608.</em>

<em>Значит вместо звездочки можно подставить цифры 0 или 1.</em>

8 0
3 years ago
What is 2*2 please answer this question
vampirchik [111]

Answer:

4

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Pls help on #10 will give brainliest
Free_Kalibri [48]
The answer is A hope this helps
4 0
3 years ago
Find an equation for the plane tangent to the surface given by z = x^2 + y^4 + e^xy
aivan3 [116]

Answer:

z = 2x + y - 2

Step-by-step explanation:

To find an equation for a plane tangent to a surface, we need two things:

1) A surface Z = f(x,y)

2) A point P(x0,y0,z0)

The equation for the plane tangent to the surface Z at the point P is given by the equation a)

a) Zx(x0,y0,z0)*(x-x0) + Zy(x0,y0,z0)*(y-y0) -(z-z0) = 0

Where Zx is the partial derivative of Z in relation to x and Zy is the partial derivative of Z in relation to y

In your problem, we have that Z = x^2 + y^4 + e^(xy)

So Zx(x,y,z) = 2x + ye^(xy)

We have that (x0,y0,z0) = (1,0,2), so Zx(1,0,2) = 2

Zy(x,y,z) = 4y^3 + xe^(xy)

Zy(1,0,2) = 1

According to equation a), we have

Zx(1,0,2)*(x-2) + Zy(1,0,2)*(y-0) -(z-2) = 0

2*(x-2) + y - z + 2 = 0

z = 2x + y - 2 is the equation for the plane tangent to this surface at this point.

7 0
4 years ago
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