All categories

2 years ago

Which choice is an equation of the line written in point-slope form?

Mathematics

1 answer:

Sladkaya [172]2 years ago

8 0

Answer:

Option 3)............... I guess so

You might be interested in

katrin2010 [14]

Answer:

gcjhgfjhg

Step-by-step explanation:

jhgfygfyitgv

3 0

2 years ago

6/10 = 1/2 true or false

vesna_86 [32]

Answer:

False

Step-by-step explanation:

When you simplify 6/10 you will realize it's 3/5 which is not the same as 1/2.

Hope this helps!

Please mark brainliest if you think I helped! Would really appreciate!

7 0

2 years ago

Hello ya'll. I have a quick question to ask ya'll.

stepladder [879]

Answer:

$3n$

Step-by-step explanation:

If the initial number is n, one less than n is n - 1, and one more than n is n + 1. so we have:

$n - 1 + n + n + 1=3n$

At first I thought this answer was too easy, so I tried for n is 6.

$3*6=18\\5+6+7=18$

This is really cool! Hope this helps!

8 0

2 years ago

Can someone please help me out

Furkat [3]

Answer:

7. The Puerto Rican Parrot's are the limiting factor in this scenario. 8. Yes because the hurricanes are limiting the Parrots population. 9. Other ways species can be limited because of the weather are either any natural disasters.

Step-by-step explanation:

Hope this helped : )

3 0

2 years ago

What are the solutions of x^2-2x+5=0

sweet [91]

The solution of $x^{2}-2 x+5=0$ are 1 + 2i and 1 – 2i

Solution:

Given, equation is $x^{2}-2 x+5=0$

We have to find the roots of the given quadratic equation

Now, let us use the quadratic formula

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$ --- (1)

Let us determine the nature of roots:

Here in $x^{2}-2 x+5=0$ a = 1 ; b = -2 ; c = 5

$b^2 - 4ac = 2^2 - 4(1)(5) = 4 - 20 = -16$

Since $b^2 - 4ac < 0$ , the roots obtained will be complex conjugates.

Now plug in values in eqn 1, we get,

$x=\frac{-(-2) \pm \sqrt{(-2)^{2}-4 \times 1 \times 5}}{2 \times 1}$

On solving we get,

$x=\frac{2 \pm \sqrt{4-20}}{2}$

$x=\frac{2 \pm \sqrt{-16}}{2}$

$x=\frac{2 \pm \sqrt{16} \times \sqrt{-1}}{2}$

we know that square root of -1 is "i" which is a complex number

$\begin{array}{l}{\mathrm{x}=\frac{2 \pm 4 i}{2}} \\\\ {\mathrm{x}=1 \pm 2 i}\end{array}$

Hence, the roots of the given quadratic equation are 1 + 2i and 1 – 2i

6 0

2 years ago