Which term best describes the movement of water thought cell membrane

The major result of the inflammatory response is to ___________________________.

oksano4ka [1.4K]

The major result of the inflammatory response is to infection or injury. Tissue level , inflammation is characterized by redness , swelling and itching which result from local immune , vascular and inflammatory cell responses .

Pathogen such as viruses, bacteria or fungi can causes of inflammation. External injuries like scrapes or damage through foreign objects effects of chemicals or radiation.The first and the earliest symptom of inflammation is silent phase which based on reaction of resident cells of the damaged tissue.

There are three main stages of inflammation which can vary from intensity or duration. such as Acute- swelling stage, sub acute- regenerative stage , regenerative stage, chronic- scar tissue maturation and remodeling stage.

To learn more about Pathogen here

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8 0

2 years ago

WHAT PROCESS ALLOWS A SPECIES TO LIVE IN ITS NICHE?

KATRIN_1 [288]

A. Evolution i think

8 0

3 years ago

One way to determine the density of animals in an area is to use the mark-recapture technique. A number of individuals from a po

NNADVOKAT [17]

Answer:

N = 187.55

Explanation:

Here you just need to replace the terms and clear the equation.

You already know that,

First capture: 25 prairie dogs.
First marked animals: 25 (the whole first capture)

You let these animals leave and then you made another capture.

Second capture: 135 prairie dogs
Already Marked animals: 18 (these 18 dogs were caught in the first capture and marked before releasing them)

To know the size of the prairie dogs population you just need to use the following equation and clear N, which is the value that you are looking for.

Number of individual marked in first catch/Total population size, N = Number of individual marked in 2nd catch / Total number of 2nd catch

Number of individual marked in first catch = 25 dogs
Total population size, N = this is what we want to know
Number of individual marked in 2nd catch = 18 dogs
Total number of 2nd catch = 135 dogs

So now, we need to replace terms

25 / N = 18 / 135

25 / N = 0.1333

N = 25 / 0.1333

N = 187.55

4 0

2 years ago

assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar

svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

$E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}} \Big )$