Answer:
<em>In the next year, Anthony worked 2,084 hours</em>
Step-by-step explanation:
Anthony worked 1,697 hours in 2010.
We also know Anthony worked 22.8% more hours than in 2010.
The problem requires to calculate how much did Anthony work in the next year.
It can be calculated as follows:
Take 22.8% of 1,697:
Now calculate by adding it to the original number of hours:
1,697 + 387 = 2,084 hours
In the next year, Anthony worked 2,084 hours
We can convert grams to kilograms by dividing by 1000.
3500÷1000=3.5kg
Now we subtract this from her original weight
65.5-3.5= 62kg
The first day of the month would be the first saturday.
<u>Answer:</u>
The correct answer option is B.
<u>Step-by-step explanation:</u>
We are given a graph with different intervals A, B, C and D and we are to figure out whether which of these intervals on the graph can be describes as linear increasing.
From the given interval options, we can see that C is constant while the intervals A and D are decreasing linear.
Its the interval B which can be describes as linear increasing since it has a positive slope.
Answer:
Future amount (A) = $1,258.77 (Approx)
Step-by-step explanation:
Given:
Amount deposit (p) = $693
Rate of interest monthly (r) = 4.9% / 12 = 0.003833
Number of month (n) = 13 × 12 = 156
Find:
Future amount (A)
Computation:
![A = p [1+r]^n \\\\ A = 693 [1+0.003833]^{156}\\\\ A= 693[1.8163]\\\\ A = 1258.77](https://tex.z-dn.net/?f=A%20%3D%20p%20%5B1%2Br%5D%5En%20%5C%5C%5C%5C%20A%20%3D%20693%20%5B1%2B0.003833%5D%5E%7B156%7D%5C%5C%5C%5C%20A%3D%20693%5B1.8163%5D%5C%5C%5C%5C%20A%20%3D%201258.77)
Future amount (A) = $1,258.77 (Approx)
