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aksik [14]
3 years ago
8

Help PLS i put you in brainlist

Mathematics
2 answers:
Lapatulllka [165]3 years ago
6 0

Answer:

1. 45 + 18

2. 77 - 35

3. 22 - 7

4. 94 + 56

5. 88 + 41

6. 43 - 29

7. 68 - 55

8. 1 + 67

9. 27 + 72

10. 97 - 93

11. 34 - 2

12. 42 + 80

hope this helps

Goryan [66]3 years ago
5 0

Answer:

1. 45 + 18

2. 77 - 35

3. 22 - 7

4. 94 + 56

5. 88 + 41

6. 43 - 29

7. 68 - 55

8. 1 + 67

9. 27 + 72

10. 97 - 93

11. 34 - 2

12. 42 + 80

Step-by-step explanation:

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I would say 25 is the answer to it
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3 years ago
 PLSSS HELP IMMEDIATELY!!!!! i’ll give brainiest, i’m not giving brainiest if u leave a link tho. (pls check whole picture!!) a
emmainna [20.7K]

Answer:

(0, 1)

Step-by-step explanation:

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4 0
3 years ago
Can someone please help me with the question, a/4 = 15/12 a=?
malfutka [58]

Answer:

a = 5

Step-by-step explanation:

a/4 = 15/12

We can use cross products to solve

a* 12 = 4*15

12a = 60

Divide each side by 12

12a/12 = 60/12

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7 0
3 years ago
Read 2 more answers
Determine the volume of the parallelepiped with one vertex at the origin and the three vertices adjacent to it at (2, â1, â1), (
valentinak56 [21]

Answer:

23

Step-by-step explanation:

Here is the complete question

Find the volume of the parallelepiped with one vertex at the origin and adjacent vertices at (1, 0, -3), (1, 2, 4), and (5, 1, 0).

Solution

We find the volume of the parallelepiped by making a 3 × 3 column matrix whose columns are the corresponding coordinates of the vertices of the parallelepiped.

So, (1, 0, -3), (1, 2, 4)  and (5, 1, 0)

A = \left[\begin{array}{ccc}1&1&5\\0&2&1\\-3&4&0\end{array}\right]

The determinant of A is the volume of the parallelepiped. So,

detA = 1(2 × 0 - 4 × 1) - 1(0 × 0 - (-3) × 1) + 5(0 × 4 - (-3) × 2)

= 1(0 - 4) - 1(0 + 3) + 5(0 + 6)

= 1(-4) - 1(3) + 5(6)

= -4 - 3 + 30

= 23

So the volume of the parallelepiped is 23

4 0
3 years ago
11r + 7s written form plz i need help
charle [14.2K]

Answer:

eleven r plus seven s

Step-by-step explanation:

thats the written form

8 0
3 years ago
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