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3 years ago

Which of the following groups of numbers are all prime numbers?

Mathematics

1 answer:

Ipatiy [6.2K]3 years ago

6 0

The answer is B because all prime numbers are multiplied by one.

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How many is 4 +1 and you add that whathat that come to

sesenic [268]

Just like counting imaginary dots on the #s

4+1=5

8 0

3 years ago

Read 2 more answers

a 10-foot section of a certain rope weighs 8 ounces. What is the length, in feet, of a section that weights 3 pounds? can you pl

Ostrovityanka [42]

Create and solve an equation of ratios:

10 ft 8 oz
------- = -------
x 48 oz (note that 3 lb = 48 oz)

Then 480 = 8x, and x = 60 ft (answer)

6 0

3 years ago

6. Let f and g be differentiable functions

Julli [10]

Answer:

(b) 1

Step-by-step explanation:

To differentiate $h(x)=f(x)g(x)$ we will need the product rule:

$h'(x)=f'(x)g(x)+f(x)g'(x)$ .

We have $h'(x)=f(x)g'(x)$ , so the following equation is true by the transitive property:

$f'(x)g(x)+f(x)g'(x)=f(x)g'(x)$

By subtraction property we have:

$f'(x)g(x)=0$

Since $g(x) \neq 0$ , then we can divide both sides by $g(x)$ :

$f'(x)=\frac{0}{g(x)}$

$f'(x)=0$

This implies $f(x)$ is constant.

So we have that $f(x)=c$ where $c$ is a real number.

Since $f(0)=1$ and $f(0)=c$ , then by transitive property $1=c$ .

So $f(x)=1$ .

Checking:

$h(x)=1 \cdot g(x)$

$h'(x)=g'(x)=1 \cdot g'(x)$

So the following conditions were met.

5 0

3 years ago

Assuming the conditions regarding the motion represented in the graph remain the same, determine the acceleration of the object

vovikov84 [41]

(a)

We can see that

this is a straight line

and this is the graph of velocity

we know that

acceleration is the derivative of velocity

so, slope of curve of velocity is acceleration

so, we will find slope of this line

We can select any two points

(0,4) and (5,7)

we can use slope formula

$m=\frac{y_2-y_1}{x_2-x_1}$

now, we can plug points

$m=\frac{7-4}{5-0}$

$m=0.6$

we know that slope of line is always constant irrespective of any value of t

so, acceleration will always be same irrespective of any value of t

so, we will get acceleration

$a(t)=0.6m/s^2$ ............Answer

(b)

we can see that acceleration is constant

and we know that

derivative of constant is always 0

so, instantaneous rate of acceleration at t=10s is 0........Answer

7 0

3 years ago

Read 2 more answers

100 PTS!! PLEASE HELP! OVER DUE

Reika [66]

Answer:

$-\frac{1}{2} \vec {c}$

Step-by-step explanation:

Look at the component form of each vector.

Note that vector c is <4,4> and vector d is <-2,-2>

If one imagined the line that contained each vector, the line for both would have a slope of 1, because $\frac{4}{4}=1=\frac{-2}{-2}$

Since they have the same slope they are parallel, but since they are in opposite directions, we often call them "anti-parallel" (simply meaning parallel, but in opposite directions).

If two vectors are parallel, one vector can be multiplied by a scalar to result in the other vector. This means that there is some number "k", such that $k \vec{c} = \vec {d}$ , or equivalently, $kc_x=d_x$ and $kc_y=d_y$ .