0.0833 to a fraction

2.) I would say something about how the A in front of cos in the equation would change to 90, rather than stay 75 (in the equation for the step by step), but it would be easier to just use the Pythagorean theorem.

Step-by-step explanation:

I think we may have the same class so hopefully this helps:

1.) $a^2 = b^2 + c^2 - 2bccosA$ --> law of cosines formula.

$a^2 = 3^2 + 3^2 - 2(3)(3)cos(75)$ --> plugged in numbers; when you draw the triangle, the included angle would be A, and the opposite side would be a. B and b, and C and c are opposite each other. In this case, a is the hypotenuse.

$a^2 = 18 - 18cos75$ --> in between steps.

$a^2 = 13.341$ --> more simplifying.

$a(hypotenuse) = \sqrt{13.341} or 3.652$ --> answer

2.) This one is just an explanation: The 75 in the equation is the given angle, which is a. If this changes, it would just change in the equation too. And obviously, if it's 90 degrees, you can just use Pythagorean theorem a^2+b^2=c^2.

Good luck! :)

6 0

3 years ago

Juan tiene cubos azules de 55 mm de arista y cubos rojos de 45 mm de arista. Los apila en dos columnas, una de cada color ; quie

balu736 [363]

the question in English

Juan has blue cubes with a 55 mm edge and red cubes with a 45 mm edge. He stacks them in two columns, one of each color; he wants the two columns to be the same height. How many cubes does he need, as a minimum, of each color?

Let

x---------> the number of blue cubes

y--------> the number of red cubes

we know that

Juan wants that the two columns to be the same height

so

$55x=45y$

solve for y

$y=\frac{55}{45}x$

I proceed to calculate a table, assuming values of x to calculate the value of y. When the values of x and y are whole numbers, I will have found the solution.

the table in the attached figure

therefore

<u>the answer is</u>

9 blue cubes

11 red cubes