Solve the following proportion 16/18 = 4/c

Mathematics

1 answer:

tamaranim1 [39]3 years ago

7 0

Answer:

16/18 4/36

Step-by-step explanation:

im sorry i dont know

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prohojiy [21]

Answer:

1.24 m

Step-by-step explanation:

F ∝ 1/d²

F = k/d²

Use values given to solve for k

0.006 = k/3²

k = 0.054 (I multiplied both sides by 3² in the equation above)

New equation is F= 0.054/d²

Plug in your numbers so 0.035 = 0.054/d²

0.054/0.035 = d²

You can simplify if you want so d² = 54/35

Square root both sides to solve for d

√54/35 = 1.24 m

3 0

3 years ago

Use rules of transformations to answer each of the items below. Be sure to answer in complete sentences, and when necessary, inc

cestrela7 [59]

We choose the coordinates (4,4), (4,10), and (8,4) as the vertices of right-angle triangle ABC

We want to dilate triangle ABC by scale factor of 2 at the center (0,2)

The image is shown below as triangle A'B'C' with coordinates (8.6), (8,18), and (18,6).

Triangle ABC has a base of 4 units and a height of 6 units
Triangle A'B'C' has a base of 8 units and a height of 12 units

Applying Pythagoras theorem to triangle ABC to find the hypotenuse
$BC^{2}= AB^{2}+ AC^{2}$
$BC^{2}= 4^{2}+ 6^{2}$
$BC^{2} =52$
$BC=2 \sqrt{13}$

Now, we calculate the hypotenuse of the image
$B'C'^{2}= A'B'^{2}+ A'C'^{2}$
$B'C'^{2}= 8^{2}+ 12^{2}$
$B'C'^{2}=208$
$B'C'= \sqrt{208} =4 \sqrt{13}$

The hypotenuse of the image is twice the hypotenuse of triangle ABC which proof the two shapes are similar shape