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Nat2105 [25]
3 years ago
8

Find the solution to the equation below.

Mathematics
1 answer:
Andreyy893 years ago
3 0

Answer:

B and D

Step-by-step explanation:

The quadratic formula is x=\frac{-b+/-\sqrt{b^2-4ac} }{2a}. Here a=20, b=-26, and c=8.

Substitute and you'll have:

x=\frac{-b+/-\sqrt{b^2-4ac} }{2a} =\frac{26+/-\sqrt{26^2-4(20)(8)} }{2(20)}=\frac{26+/-\sqrt{676-640} }{40)}

\frac{26+/-\sqrt{36} }{40}=\frac{26+/-6 }{40}

This means the solutions are 26 - 6/ 40 and 26 + 6/ 40.

It simplifies to 1/2 and 4/5.

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A right cone has a radius of 13 cm and a slant height of 20 cm. Find its surface area.
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Answer:

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Step-by-step explanation:

Given that,

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A=\pi r(l + r)\\\\A=\pi \times 13(20 + 13)\\\\A=1347.7\ cm^2

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