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2 years ago

I will give 30 points to whoever answers this correctly and within 5-10 mins.

Mathematics

1 answer:

natali 33 [55]2 years ago

8 0

Answer:

1)The dimensions you are solving for

length of the rectangular room

width of the rectangular room

2)Now let the length be L and the width be w then

the perimeter is 2L+2W

2L+ 2W = 24------------------------------(1)

Also, "Twice the length decreased by three times the width is 4 feet" can be written as

2L - 3W = 4-------------------------------------(2)

Solving (1) and (2) by elimination method, by subtraction

2L+ 2W = 24

2L - 3W = 4

(-) (-) (-)

----------------------------

0L +5W = 20

-----------------------------

5W = 20

W = 4--------------------------------------------(3)

Now by substitution method,substituting (3) in(1)

2L+ 2(4) = 24

2L + 8 = 24

2L = 24 -8

2L = 16

L = 8

Substituting in the original equation and rechecking the perimeter

=2(8) + 2(4)

=16 + 8

= 24

Thus the found dimensions are correct

3)The length of the room is 8 feet and the width of the room is 4 feet.

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