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OlgaM077 [116]
3 years ago
5

(2x+1)(x+5) 6x-4xy 16x^2-25

Mathematics
2 answers:
timofeeve [1]3 years ago
8 0
-32xy-25 try dat anyways have a nice dayyyy byeeeee
Vesna [10]3 years ago
3 0

Step-by-step explanation:

i believe what you need help on is simplifying the equations. so let's start with the first one.

====================================================================

(2x+1)(x+5) original problem

(2x)(x)+(2x)(5)+(1)(x)+(1)(5) we can break this down into smaller pieces so we know what we're dealing with in this equation.

2x2+10x+x+5 if we break this down a little more and add some bracket numbers, this is what we get.

2x2+11x+5 <em>this is the most simplified equation.</em>

====================================================================

6x−4xy original problem.

unlike the last problem, we can easily just... <em>6x + (−4xy)</em>.

−4xy+6x <em>this is the most simplified equation.</em>

====================================================================

ok, the last one. phew!

unfortunately, 16x^2-25 is actually the simplest it can get. so, let's try factoring.

if we factored, we would get...

(4x+5)(4x−5)

===================================================================

hope this helps! :>

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Please solve i will give brainiest 100 point question ****** do the whole page please need to pass or i will fail its my final t
dmitriy555 [2]

Answer:

1. Find the difference between the areas.

<u>Area of the small rectangle</u>: (x+2)(x+7)=x^2+7x+2x+14=x^2+9x+14

<u>Area of the big rectangle</u>: (x+9)(x+11)=x^2+11x+9x+99=x^2+20x+99

The difference is: 11x+85

( x^2+20x+99)- (x^2+9x+14)=x^2+20x+99-x^2-9x-14=11x+85

2.

You can solve this question just by looking at the graph.

a) The height is 4 meters.

f(d)=h=-2d^2+7d+4

To find the height of the bleachers, we should consider the moment before the shoot, when the distance is equal to 0.

f(0)=h=-2(0)^2+7(0)+4

h=4

The height is 4 meters.

b) 9 meters.

For d=1

f(1)=h=-2(1)^2+7(1)+4

f(1)=h=-2+7+4

h=9

b) The ball travels 4 meters.

But to calculate it, it is when h=0

0=-2d^2+7d+4

Using the quadratic formula:

$d=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$d=\frac{-7 \pm \sqrt{7^2-4\left(-2\right)4}}{2\left(-2\right)}$

$d=\frac{-7\pm\sqrt{81}}{-4}$

$d=\frac{-7\pm9}{-4}$

It will give us to solutions, once it is a quadratic equation, but we are talking about a positive distance.

$d=-\frac{1}{2} \text{ or }d=4$

3.

In this question, we have to find the area of the cylinder and the sphere.

From the information given, we have

a = 5mm and d = 5mm, therefore the radius is 2.5 mm.

The volume of a cylinder:

V=\pi r^2h

V=\pi (2.5)^2 \cdot 5

V=31.25 \pi

V_{c} \approx 98.17 \text{ m}^3

The volume of the sphere:

$V=\frac{4}{3}  \pi r^2$

V_{s} \approx 65.4 \text{ m}^3

The volume of the capsule is approximately 163.57  \text{ m}^3

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Helen [10]
I believe that it is B. Hope this helps!
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What is the solution of the following? *<br> -4 = 16<br> Infinite solutions<br> no solution
rjkz [21]

Answer: no solution

Hope this helps and good luck :)

Step-by-step explanation:

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