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Anton [14]
3 years ago
10

Among 39- to 44-year-olds, 35​% say they have called a talk show while under the influence of peer pressure. Suppose seven 39 to

44​-year-olds
are selected at random.
​(a) What is the probability that at least one has not called a talk show while under the influence of peer pressure
​
​(b) What is the probability that at least one has called nbsp a talk show while under the influence of peer pressure​?

​(a) The probability that at least one has not called a talk show
while under the influence of peer pressure is?
.
​(Round to four decimal places as​ needed.)
​(b) The probability that at least one of the seven randomly selected adults has called a talk show while under the influence of peer pressure is?
​(Round to four decimal places as​ needed.)
Mathematics
1 answer:
LenKa [72]3 years ago
8 0
<span>if 35% or 0.35 say no, to compute the probability that at least one of 7 </span>called a talk show while under the influence of peer pressure <span> is (1-0.35)^7  and subtract it from . This is the same as at least 1 has </span><span>called a talk show while under the influence of peer pressure
</span><span>1 - (1 - 0.35)^7 = 0.95
  </span>
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