A toy cost 0.85p in January.
Step-by-step explanation:
Given,
Mark down in January = 15%
Let,
Price in December = p
Mark down in January = 15% of price in December
Mark down in January = 
Mark down in January = 0.15p
Price of toy in January = Price in December - Mark down
Price of toy in January = p - 0.15p = 0.85p
A toy cost 0.85p in January.
Keywords: mark down, subtraction
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If rooster = 6 eggs =10 banana = 5 and 6+10x5= 56
The answer is (5,3) because when a point gets reflected across the x-axis its x coordinate stays the same but its y coordinate switches sign
The range is the set of all y-coordinates.
R = {2, 6, 8}
Swapping rows alters the sign of the determinant:

Multiplying a single row by a scalar scales the determinant by the same amount:

Then
