Answer:
A fair die has 6 sides.
There are 3 odd numbers on a fair die so the probability would be 3/6
There are 4 numbers greater than 2 on a fair die o the probability of that would be 4/6
There is only one number that will make it square and that is 4. So the probability would be 1/6
Answer:
Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:
a=√{b²+c²−2bc×cos40°}
a=√{149.645−149.645cos40°}
Area Nonagon = (9/4)a²cos40°
=9/4[149.645−149.645cos40°]cot20°
=336.70125[1−cos(40°)]cot(20°)
Applying an identity for the cos(40°) does not get us very far…
= 336.70125[1−(cos2(20°)−1)]cot(20°)
= 336.70125[2−cos2(20°)]cot(20°)
= 336.70125[2−(1−sin2(20°))]cot(20°)
= 336.70125[1+sin2(20°)]cos(20°)sin(20°)
= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²
Answer:
C. 2• 3 • x • x
Step-by-step explanation:
Not sure but that's what I would guess
Answer:
Below.
Step-by-step explanation:
Let x be the Annika's weekly income.
2/25 of x = 42
2x/25 = 42
x = 42(25/2)
x = 525
Her weekly income is $525.
65.8 + 13.4 = 79 .2. So the answer is c
