All categories

3 years ago

Hey can you please help me posted picture of question

Mathematics

1 answer:

Nataliya [291]3 years ago

3 0

Total number of blue candies = 20 + 30 = 50
Number of blue candies without nut = 20

Probability of picking a blue candy without a nut = (Number of blue candies with nut) /(Total number of blue candies)

So, Probability of picking a blue candy without a nut = $\frac{20}{50} =0.4=40$ %

Thus, the correct answer is option A

You might be interested in

Circle two words that describe each triagle

dlinn [17]

You're going to need to take a picture of the triangles.

7 0

3 years ago

Read 2 more answers

Jim pays $75 per month for a cell phone plan plus $0.30 per minute beyond the first 1000 minutes. Write an equation for the cost

iragen [17]

The answer is 75+ 0.30(x) = y

8 0

3 years ago

Read 2 more answers

3 lines are shown. A line with points C, A, F intersects a line with points B, A, E at point A. A line extends from point A to p

JulsSmile [24]

Answer:

A 45

Step-by-step explanation:

edge 2020

6 0

3 years ago

Read 2 more answers

Study the image. Global winds. Blue arrows designate cool air. Red arrows designate warm air. Cool air moves from the South and

nydimaria [60]

Answer:

is there supposed to be a image there for us to see or no?

3 0

2 years ago

Read 2 more answers

If we inscribe a circle such that it is touching all six corners of a regular hexagon of side 10 inches, what is the area of the

Brrunno [24]

Answer:

$\left(100\pi - 150\sqrt{3}\right)$ square inches.

Step-by-step explanation:

<h3>Area of the Inscribed Hexagon</h3>

Refer to the first diagram attached. This inscribed regular hexagon can be split into six equilateral triangles. The length of each side of these triangle will be $10$ inches (same as the length of each side of the regular hexagon.)

Refer to the second attachment for one of these equilateral triangles.

Let segment $\sf CH$ be a height on side $\sf AB$ . Since this triangle is equilateral, the size of each internal angle will be $\sf 60^\circ$ . The length of segment

$\displaystyle 10\, \sin\left(60^\circ\right) = 10 \times \frac{\sqrt{3}}{2} = 5\sqrt{3}$ .

The area (in square inches) of this equilateral triangle will be:

$\begin{aligned}&\frac{1}{2} \times \text{Base} \times\text{Height} \\ &= \frac{1}{2} \times 10 \times 5\sqrt{3}= 25\sqrt{3} \end{aligned}$ .

Note that the inscribed hexagon in this question is made up of six equilateral triangles like this one. Therefore, the area (in square inches) of this hexagon will be:

$\displaystyle 6 \times 25\sqrt{3} = 150\sqrt{3}$ .

<h3>Area of of the circle that is not covered</h3>

Refer to the first diagram. The length of each side of these equilateral triangles is the same as the radius of the circle. Since the length of one such side is $10$ inches, the radius of this circle will also be $10$ inches.

The area (in square inches) of a circle of radius $10$ inches is:

$\pi \times (\text{radius})^2 = \pi \times 10^2 = 100\pi$ .

The area (in square inches) of the circle that the hexagon did not cover would be:

$\begin{aligned}&\text{Area of circle} - \text{Area of hexagon} \\ &= 100\pi - 150\sqrt{3}\end{aligned}$ .

3 0

3 years ago