Hey can you please help me posted picture of question
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Answer:
Step-by-step explanation:
Given equation is,
y = 3x² - 6x + 11
a). y = 3x² - 6x + 11
= 3(x² - 2x) + 11
= 3(x² -2x + 1 - 1) + 11
= 3(x² - 2x + 1) - 3 + 11
= 3(x - 1)² + 8
Comparing this equation with y = a(x - b)² + c
a = 3, b = 1 and c = 8
b). For minimum value of x,
Since, vertex of the graph is given by (b, c),
Minimum value of x will be,
x = b
x = 1
c). Vertex of the parabola → (b, c)
→ (1, 8)
For y-intercept,
By substituting x = 0 in the equation,
y = 3(0 - 1)² + 8
y = 11
Now we can sketch the graph by using the table of input - output values.
x -2 -1 0 1 2 3
y 35 20 11 8 11 20
