Answer:
This question is incomplete as it lacks options, the options are:
Which change would be the most effective way to improve the validity of this experiment?
A) Increase the number of goldfish in each tank.
B) Increase the daily amount of food for each tank.
C) Create another group that is fed regular fish food.
D) Increase the number of tanks in each treatment group.
The answer is C
Explanation:
According to this question, an experiment is conducted by Trey to determine which fish food causes the most goldfish activity over a period of two weeks. In this experiment, the independent variable is the FISH FOOD which are; Swift Salmon food and Fast Flounder food. Other variables such as type of gold fish, amount of fish food, amount & type of water etc.
One of the ways to improve an experiment, which is lacking in this case is to have a CONTROL GROUP. Based on the fish foods used for each group, it is obvious that all groups in this experiment are experimental. Hence, creating another group that is fed regular fish food will serve as the CONTROL GROUP in order to compare with the experimental groups. This will improve the validity of the experiment.
Answer:
The acceleration of the snowball is 0.3125
Explanation:
The initial speed of the snowball up the hill, u = 0
The speed the snowball reaches, v = 5 m/s
The length of the hill, s = 40 m
The equation of motion of the snowball given the above parameters is therefore;
v² = u² + 2·a·s
Where;
a = The acceleration of the snowball
Plugging in the values, we have;
5² = 0² + 2 × a × 40
∴ 2 × 40 × a = 5² = 25
80 × a = 25
a = 25/80 = 5/16
a = The acceleration of the snowball = 5/16 m/s².
The acceleration of the snowball = 5/16 m/s² = 0.3125 m/s² .
Answer:
By using Pythagoras Formula
Explanation:
Measure the distance man is sliding. “It will be c”
Measure the distance of between the tower and a post with which wire is attached. It will be “b”
Then apply Pythagoras Formula c2=a2 + b2 and solve it.
It will give the height of tower.
Answer: Recall that
Work (W) = - e × ∆V
Where
Charge of electron= 1.6 × 10^ -19 c
And from the question we were given change in potential as = -0.0677V
Work = - (1.6 × 10^-19) × (-0.0677)
Work= 1.0832 × 10^-20J
Therefore the work done by the electric force when a sodium ion (charge = +e) moves from the outside to the inside is 1.0832×10^-20
