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Bumek [7]
2 years ago
12

The specific resistance of wire​

Physics
1 answer:
Assoli18 [71]2 years ago
3 0

Answer:

a material is the resistance offered by a wire of the material which is 1 foot long with a diameter of one MIL. The resistance of a wire is directly proportional to the specific resistance of the material.

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Adhesion is when forces of the molecules are more strongly drawn to each other than the molecules in other substances true or fa
SSSSS [86.1K]

Answer:

False

Explanation:

that is cohesion. adhesion is force between dissimilar molecules of a body

6 0
3 years ago
The two properties of an electron that cannot be known exactly at the same time are the ____________________.
enyata [817]
Position and momentum.

This is Heisenberg's Uncertainty Principle:
Δx Δp ≥ h ÷ 4π,   where Δx is the change in position, Δp is the change in momentum, and h is Planck's Constant.
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3 years ago
Who was Georges Lemaitre and how did he contribute to the Big Bang theory?<br> (15 points)
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A Belgian Astronomer and Cosmotologist who formulated the modern Big Bang theory, which states that the universe began in a cataclysmic explosion of a small, primeval “super-atom”
7 0
3 years ago
15 POINTS
zhenek [66]

Answer:

Acceleration of the bullet while moving into the clay is -312500 ms⁻²

Explanation:

Given data

Initial velocity (v₁) = 250 m/s                 Final velocity (v₂) = 0 m/s

Distance (s)= 0.1 m                            acceleration (a) = ?

Using 3rd equation of motion

                  2as = v₂²- v₁²

       2 × a × 0.1 = 0² - 250²

            0.2 × a = -62500

                      a = -62500/0.2

                     a = -312500 m/s²

Here negative sign indicate that bullet slow down and it is deceleration i.e negative acceleration.

3 0
3 years ago
Web Spiders and Oscillations All spiders have special organs that make them exquisitely sensitive to vibrations. Web spiders det
Leokris [45]

Answer:

0.037 N/m

Explanation:

The web acts as a spring, so it obeys Hook's law:

F=kx (1)

where

F is the force exerted on the web

k is the spring constant

x is the stretching/compression of the web

In this problem, we have:

- The mass of the fly is m=15 mg=15\cdot 10^{-6} kg

- The force exerted on the web is the weight of the fly, so:

F=mg=(15\cdot 10^{-6}kg)(9.81 m/s^2)=1.47\cdot 10^{-4}N

- The stretching of the web is

x=4.0 mm=0.004 m

So if we solve eq.(1) for k, we find the spring constant:

k=\frac{F}{x}=\frac{1.47\cdot 10^{-4} N}{0.004 m}=0.037 N/m

3 0
3 years ago
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