Question

A coin has a radius of 1.06 cm and a thickness of 1.2 mm. Find its volume in m^3.

Answer 1

Answer:

The volume of the coin is 4.236 x 10⁻⁷ m³

Explanation:

Given;

radius of a coin, r = 1.06 cm = 0.0106 m

thickness of the coin, h = 1.2 mm = 0.0012 m

The volume of the coin is given by;

volume = Area x thickness

Area of the coin = πr² = π (0.0106)² = 3.5304 x 10⁻⁴ m²

The volume of the coin = (3.5304 x 10⁻⁴ m²) x (0.0012 m)

The volume of the coin = 4.236 x 10⁻⁷ m³

Therefore, the volume of the coin is 4.236 x 10⁻⁷ m³