Answer:
The volume of the coin is 4.236 x 10⁻⁷ m³
Explanation:
Given;
radius of a coin, r = 1.06 cm = 0.0106 m
thickness of the coin, h = 1.2 mm = 0.0012 m
The volume of the coin is given by;
volume = Area x thickness
Area of the coin = πr² = π (0.0106)² = 3.5304 x 10⁻⁴ m²
The volume of the coin = (3.5304 x 10⁻⁴ m²) x (0.0012 m)
The volume of the coin = 4.236 x 10⁻⁷ m³
Therefore, the volume of the coin is 4.236 x 10⁻⁷ m³
