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Artemon [7]
3 years ago
13

In the figure above, AB is tangent to the circle with center O

Mathematics
1 answer:
Radda [10]3 years ago
6 0

<u>Given</u>:

Given that O is the center of the circle.

AB is tangent to the circle.

The measure of ∠AOB is 68° and we know that the tangent meets the circle at 90°

We need to determine the measure of ∠ABO.

<u>Measure of ∠ABO:</u>

The measure of ∠ABO can be determined using the triangle sum property.

Applying the property, we have;

\angle ABO+\angle BAO+\angle AOB=180^{\circ}

Substituting the values, we get;

\angle ABO+90^{\circ}+68^{\circ}=180^{\circ}

Adding the values, we have;

\angle ABO+158^{\circ}=180^{\circ}

Subtracting both sides by 158, we get;

\angle ABO=22^{\circ}

Thus, the measure of ∠ABO is 22°

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How do you solve this triangle by using the law of sine where
mars1129 [50]
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c^2 = a^2 + b^2 -2ab * cos(C)
c^2 = 36 + 16 - 2*6*4 * cos(60)
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Using the Law of Sines
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5.2915 / sin(60) = 4 / sin (B)
sin(B) = sin(60) * 4 / 5.2915
sin(B) = 0.86603 * 4 / 5.2915
<span><span>sin(B) = 3.46412 </span> / 5.2915
</span> <span><span><span>sin(B) = 0.6546571451 </span> </span> </span> 
Angle B = 40.894 Degrees

sin (A) / side a = sin (B) / side b
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7 0
4 years ago
I need to solve for A. <br> Please help! Thank you!
nlexa [21]

Step-by-step explanation:

125 is vertically opposite to the interior angle of triangle

then X+40+X+31+125=180(sum of angle of triangle is 180)

the we get X= -22

8 0
3 years ago
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