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Artemon [7]
3 years ago
13

In the figure above, AB is tangent to the circle with center O

Mathematics
1 answer:
Radda [10]3 years ago
6 0

<u>Given</u>:

Given that O is the center of the circle.

AB is tangent to the circle.

The measure of ∠AOB is 68° and we know that the tangent meets the circle at 90°

We need to determine the measure of ∠ABO.

<u>Measure of ∠ABO:</u>

The measure of ∠ABO can be determined using the triangle sum property.

Applying the property, we have;

\angle ABO+\angle BAO+\angle AOB=180^{\circ}

Substituting the values, we get;

\angle ABO+90^{\circ}+68^{\circ}=180^{\circ}

Adding the values, we have;

\angle ABO+158^{\circ}=180^{\circ}

Subtracting both sides by 158, we get;

\angle ABO=22^{\circ}

Thus, the measure of ∠ABO is 22°

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